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Straight line equation: 3x+4y-16 = 0

Perpendicular equation: 4x-3y-13 = 0

Point: (7, 5)

Equations intersect: (4, 1)

Perpendicular distance: square root of [(7-4)2+(5-1)2] = 5

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โˆ™ 2012-04-18 12:25:10
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Q: What is the perpendicular distance from the point 7 and 5 to the straight line equation of 3x plus 4y minus 16 equals 0?
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