If you mean the perpendicular distance from the coordinate of (7, 5) to the straight line 3x+4y-16 = 0 then it works out as 5 units.
The distance is 5.
The line "x = 6" will be perpendicular to any line "y = C", where C is any constant. That means that the line which is perpendicular to "x=6" and passes through [-4, 5] will be "y = 5"
The line perpendicular to a surface at a point is called the normal
The slope of the perpendicular is -(1/2) .
That would depend on its slope which has not been given.
I believe the answer is "perpendicular line". Forgive me if I'm wrong :)
The perpendicular postulate states that if there is a line, as well as a point that is not on the line, then there is exactly one line through the point that is perpendicular to the given line.
It the point is on the line the distance is 0. If the point is not on the line, then it is possible to draw a unique line from the point to the line which is perpendicular to the line. The distance from the point to the line is the distance along this perpendicular to the line.
Perpendicular equation: x+2y = 0 Point of intersection: (2, -1) Perpendicular distance: square root of 5
No, they are perpendicular.
If a line has equation y = mx + c, the perpendicular line has gradient -1/m A line perpendicular to 3x + y = 2 has equation 3y = x + c; the value for c will be determined by a point through which the line must pass.
The lines are perpendicular, and intersect at the point (1.35, 3.55) .
The line "x = 6" will be perpendicular to any line "y = C", where C is any constant. That means that the line which is perpendicular to "x=6" and passes through [-4, 5] will be "y = 5"
The line perpendicular to a surface at a point is called the normal
The shortest path is a line perpendicular to the given line that passes through the given point.
the line x=6 is a vertical line intersecting the x axis at point (6,0). the line y=6 is a hortizontal line itnersecting the y axis at point (0,6). these lines are perpendicular to each other.
The point
It would be perpendicular to a line with the equation Y = 1/8 X.