The first one is in tens place and the second is in tenths place.
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∙ 12y ago161 is evenly divisible by: 1, 7, 23, 161.
1, 7, 161.
Its face value is 1 but its place value is 10
Yes: 1, 7, 23, 161.
The value of a digit: In 12,345 , the value of the digit 5 is 5 and the value of the digit 1 is 10,000. Place value: In 13,563 ,the place value of the digit 3 is thousands and the place value of the digit 6 is tens. The value of a digit is its value, as in 0-9 The place value of a digit is its value multiplied by its place (column) value which is dependant upon where it is in the number. In the units column, the place value is 1 In the tens column, it is 10 in the hundreds column it is 100 in the tenths column it is 1/10 So in 123.4: The digit 1 has value 1, but place value 1 x 100 = 100 (one hundred) since it is in the hundreds column The digit 2 has value 2, but place value 2 x 10 = 20 (twenty) since it is in the tens column The digit 3 has value 3, but place value 3 x 1 = 3 (three) since it is in the units column - in this case (only), its value and place value are the same. The digit 4 has value 4, but place value 4 x 1/10 = 4/10 (four tenths) since it is in the tenths column.
Because the place value means, where the digit is located with respect to a decimal point. 1 is always 1, but if you place 1 in the tens place value, then the value of that 1 is 10. In the hundreds place value, the value of that 1 is 100. In the hundredths place value, then the value of that 1 is .01.
161 can be divided evenly by: 1, 7, 23, 161.
161 is evenly divisible by: 1, 7, 23, 161.
If ( mn = 161 ), then ( m = \frac{161}{n} ). Without knowing the value of ( n ), it is not possible to determine the value of ( mm ).
1 x 161 = 161
1, 7, 23, 161
1, 7, 161.
Its face value is 1 but its place value is 10
1, 7, 23, 161
1, 7, 23, 161.
There are only 4 factors of 161 and they are 1, 7, 23 and 161.
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