The first one is in tens place and the second is in tenths place.
161 is evenly divisible by: 1, 7, 23, 161.
Its face value is 1 but its place value is 10
1, 7, 161.
Yes: 1, 7, 23, 161.
The number 1. 1 in the one's place equals 1.
Because the place value means, where the digit is located with respect to a decimal point. 1 is always 1, but if you place 1 in the tens place value, then the value of that 1 is 10. In the hundreds place value, the value of that 1 is 100. In the hundredths place value, then the value of that 1 is .01.
161 can be divided evenly by: 1, 7, 23, 161.
161 is evenly divisible by: 1, 7, 23, 161.
1 x 161 = 161
1, 7, 23, 161
Its face value is 1 but its place value is 10
1, 7, 161.
1, 7, 23, 161
1, 7, 23, 161.
There are only 4 factors of 161 and they are 1, 7, 23 and 161.
The place value of 8 = 8 * 100 = 800. The place value of 1 = 1 * 10 = 10. The place value of 2 = 2 * 1 = 2. The solution above and all other place value
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