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If: 5x+7y+29 = 0 and 11x-3y-65 = 0

Then: 5x+7y = -29 and 11x-3y = 65

Multiply all terms in the 1st equation by 11 and all terms in the 2nd equation by 5

So: 55x+77y = -319 and 55x-15y = 325

Subtract the 1st equation from the 2nd equation: 92y = -644 => y = -7

Therefore by substitution the point of contact is at: (4, -7)

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Q: What is the point of contact when the lines of 5x plus 7y plus 29 equals 0 and 11x -3y -65 equals 0 intersect each other showing work?
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