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If: y = 2x then y^2 = 4x^2

If: x^2 +y^2 -8x -y +5 = 0 then x^2 +4x^2 -8x -2x +5 = 0

Collecting like terms: 5x^2 -10x +5 = 0

Dividing all terms by 5: x^2 -2x +1 = 0

Factorizing the above: (x -1)(x -1) = 0 meaning x = 1

By substitution into the original equation contact is made at: (1, 2)

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Q: What is the point of contact when the tangent line y equals 2x touches the curve x2 plus y2 -8x -y plus 5 equals 0?
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