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What is the population density of 45 sand crabs in a 5 meter by 3 meter section?
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∙ 12y ago
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∙ 12y ago
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If Students counted forty five sand crabs in a 5 by 3 meter section of a beach what was the population density of the sand crabs?
The population density of sand crabs in that section of the beach is 3 sand crabs per square meter. This is calculated by dividing the total count of sand crabs (45) by the area of the section (5 meters * 3 meters = 15 square meters). Therefore, 45 sand crabs / 15 square meters = 3 sand crabs per square meter.
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El Istole in Colombia (south america) has a population desity of 1.2 persons per square meter.
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Wild crickets living in a field have a population density of 2 4 crickets m2 if the fields area is 250m2 what is the aproximite size of the cricket population why would the population density of?
TANK 1 With 200 crickets occupying an area of 0.80 square meters, that gives a population density of . . 200 crickets -------------------------- = ? crickets / square meter 0.80 square meters Is that amount < or = or > the maximum of 210 crickets / square meter?. = = = = = = = = = = = = = = = = = = = = = = = = = TANK 2 With 150 crickets occupying an area of 0.80 square meters, that gives a population density of . . 150 crickets --------------------------- = ? crickets / square meter 0.80 square meters Is that amount < or = or > the maximum of 210 crickets / square meter?. = = = = = = = = = = = = = = = = = = = = = = = = = TANK 3 With 315 crickets occupying an area of 1.5 square meters, that gives a population density of . . 315 crickets ------------------------- = ? crickets / square meter 1.5 square meters Is that amount < or = or > the maximum of 210 crickets / square meter?. = = = = = = = = = = = = = = = = = = = = = = = For PROBLEM #1, when you move crickets from tank to tank, remember to change the value of the numerators in the fractions above. EXAMPLE If you remove 10 crickets from tank 2 and put them in tank 3, then decrease tank 2's numerator from 150 to 140 and increase tank 3's numerator from 315 to 325. For PROBLEM #2, we need to rearrange the formula from above (number of crickets) -------------------------- = population density . . . . (area) Multiply both sides of the equal sign by (area). (area)(number of crickets) ----------------------------------- = (area)(population density) . . . . . . . (area) Notice how the (area) on the left side cancels out? (number of crickets) = (area)(population density) (number of crickets) = (250 square meters)(2.4 crickets / square meter) (number of crickets) = ?
If you count 20 beetles in a garden measuring 5 square the population density of the beetles is?
4 beetles per square unit meter!!!!!!!!!!!!!
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