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What is the possible number of symmetric relations on a set of 5 elements?
Wiki User
∙ 10y ago
The number is 5! = 120
Wiki User
∙ 10y ago
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What is the possible number of reflexive relations on a set of 5 elements?
2 power 20
What is the dimension of a skew symmetric matrix of order 3?
In a skew symmetric matrix of nxn we have n(n-1)/2 arbitrary elements. Number of arbitrary element is equal to the dimension. For proof, use the standard basis.Thus, the answer is 3x2/2=3 .
Is it true the number of elements in the sample space of an event is equal to the total number of possible outcomes?
true
Why is the number 5 symmetric?
5 expressed as a Roman numeral is V which is symmetrical
What geometric shape will have the most lines of symmetry?
A circle is symmetric about ANY diameter. The number of possible diameters of the same circle is infinite. And on the same principle, a sphere will have lines of symmetry in every direction in 3 dimensions.
How do you Derive The Number of symetric relation of a Set 's' having n elements?
2^(n^2+n)/2 is the number of symmetric relations on a set of n elements.
What is the total number of reflexive and symmetric relations on a set containing n elements?
the total no of reflexive relation on an n- element set is 2^(n^2-n).
What is the possible number of reflexive relations on a set of 5 elements?
2 power 20
How do you Derive The Number of reflexive relation of a Set 's' having n elements?
make a table as I did below for the set {a,b,c} with 3 elements. A table with all n elements will represent all the possible relations on that set of n elements. We can use the table to find all types of relations, transitive, symmetric etc. | a | b | c | --+---+---+---+ a | * | | | b | | * | | c | | | * | The total number of relations is 2^(n^2) because for each a or b we can include or not include it so there are 2 possibilities and there are n^2 elements so 2^(n^2) total relations. A relation is reflexive if contains all pairs of the form {x,x) for any x in the set. So this is the diagonal of your box. THESE ARE FIXED! No, in reflexive relation we still can decide to include or not include any of the other elements. So we have n diagonal elements that are fixed and we subtract that from n^2 so we have 2^(n^2-n) If you do the same thing for symmetric relations you will get 2^(n(n+1)/2). We get this by picking all the squares on the diagonal and all the ones above it too.
What does an elements location tell you about that element?
It tells you the atomic number, the number of protons, the density, its relations to other elements, and its characteristics.
What is the dimension of a skew symmetric matrix of order 3?
In a skew symmetric matrix of nxn we have n(n-1)/2 arbitrary elements. Number of arbitrary element is equal to the dimension. For proof, use the standard basis.Thus, the answer is 3x2/2=3 .
Is 22 a symmetric number?
Yes.
Is 38 a symmetric number?
yes
Roughly how many elements are there?
90 naturally occurring elements, unknown number possible elements.
Do any two elements have the same atomic number?
no that's not possible
Is there a symmetric factor tree for every composite number?
It depends what you mean by symmetric. If you mean that there are the same number of factors on each branch, then the answer is No. eg 20 / \ 4 5 / \ 2 2
What are symmetric prime?
Two primes are symmetric primes of a natural number (n) if their average is n. For example 10, has two pairs of symmetric primes. 7 and 13, and 3 and 17 because their averages are 10.
