Start by listing out all pairs of numbers greater than 0 and less than or equal to 120 that have a product equal to 120:
120 = 1 x 120
120 = 2 x 60
120 = 3 x 40
120 = 4 x 30
120 = 5 x 24
120 = 6 x 20
120 = 8 x 15
120 = 10 x 12
So, there are 8 factor pairs of 120. Now, show the prime factorization for 120 by expressing it as the product of ALL prime numbers:
120 = 2 x 60 <--- 2 is a prime number
Next step is to reduce 60 to the product of prime numbers: 60 = 3 x 20 <--- 3 is a prime number.
Next step is to reduce 20 to the product of prime numbers: 20 = 5 x 4 <--- 5 is a prime number.
Next step is to reduce 4 to the product of prime numbers: 4 = 2 x 2 <--- 2 is a prime number.
The final step is to reduce 2 to the product of prime numbers:
The prime factorization of 122 is: 2 × 61 The prime factorization of 35 is: 5 × 7 The prime factorization of 120 is: 2 × 2 × 2 × 3 × 5 The prime factorization of 15 is: 3 × 5
120 = 2x2x2x3x5 = 23x31x51
120 has the prime factorization 8 x 3 x 5
I know thhe answer for this is 1 because a prime number is one and itself , therefore the factorization for this is basically 120x1=120.
Every positive composite number only has one unique prime factorization.
It is: 2*2*2*3*5 = 120
4 isn't a prime number.
Because 4 is not a prime number.
Every positive composite number only has one unique prime factorization.
answer plz
120 = 23 x 31 x 51
23 * 3 * 5 = 120