What is the prime factorization of 63 using factor tree?

Answer 1

Prime Factor tree of 63.

We note that '63' is an odd number , because it does NOT end in 0,2,4,6,8

So it will not divide by ;2

So we try the next Prime number, which is '3'

3)63 = 21 Keep on dividing by '3' until it will not divide any further by '3'

3)21 = 7 Since '3' will not divide into '7' and '7' is a prime number, divide '7' into itself , to reduce to '1'

7)7 = 1

So the prime factor tree/stepladder of '63' is 3,3,7.

This can be expressed as 3^(2) x 7^(1) = 3^(2) x 7 .

Answer 2

As a product of its prime factors: 3*3*7 = 63

Answer 3

63

21,3

7,3,3