The probability of drawing a red card and a spade in two cards is the probability of drawing a red card multiplied by the probability of drawing a spade, multiplied by 2 (as it doesn't matter which way around they are drawn).
The probability of drawing a spade is 1/13 as there are 4 spades and 52 cards.
The probability of drawing a red card after this is 26/51 if the spade was black, and 25/51 if the spade was red. This averages at 51/102
Multiply these probabilities together and then multiply by two and we get 51/663 which can be simplified to 1/13
(1 in 52) times (1 in 52), or 1 in 2704, or about 0.0003698.
2 in 52, or 1 in 26, or about 0.03846.
.307 0r 30.7%
If only two cards are drawn from a standard deck of cards, with the first card replaced before drawing the second, the answer is 0.005917 (approx). If the first card is not replaced, the probability increases to 0.006033.
The answer depends on whether or not the first card is replaced before drawing the second.
2 in 52, or 1 in 26, or about 0.03846.
The probability of drawing a spade in a standard 52 card deck is 13 in 52, or 1 in 4. The probability of drawing a second spade, assuming the first spade was not replaced back into the deck, is 12 in 51. The probability, then, of drawing two spades is the product of those two probabilities, or 12 in 204, or 1 in 17.
Clearly, it is necessary to draw at least two cards. How many are drawn? Are the cards drawn at random? Is the first replaced before drawing the second? Please edit the question to include more context or relevant information.
The answer depends on whether or not the first card is replaced before the second is drawn.
The answer depends on whether the first number is replaced before picking the second. If not, the probability is 0.029
The probability of drawing the first face card is 12 in 52. The probability of drawing the second is 11 in 51. The probability of drawing the third is 10 in 50. Thus, the probability of drawing three face cards is (12 in 52) times (11 in 51) times (10 in 50) or (1320 in 132600) or about 0.009955.
If you are drawing two cards from a full deck of cards (without jokers) then the probability will depend upon whether the the first card is replaced before the second is drawn, but the probability will also be different to being dealt a hand whilst playing Bridge (or Whist), which will again be different to being dealt a hand at Canasta. Without the SPECIFIC context of the two cards being got, I cannot give you a more specific answer.
it depends on the total number of marbles you have!
The probability of drawing the Ace of Spades on the first draw is 1 in 52. The probability of drawing the Queen of Hearts on the second draw is 1 in 51. The probability of both of those event occurring is 1 in 2652. (1 in 52) times (1 in 51)
The probability of drawing 2 cards that are two's from a standard deck of 52 playing cards is 1 in 221. The probability of drawing the first two is 4 in 52 or 1 in 13. The probability of drawing the second two is 3 in 51. Multiply those two probabilities together and you get 3 in 663, or 1 in 221.