Best Answer

If you are drawing only two cards, the probability that they will both be aces is one in 221. ( (52 / 4) * (51 / 3) )

If you are drawing all the cards in the deck, one at a time, the probability that you will draw at least two aces in a row is much better than that, but how much better I leave for someone else to answer.

Q: What is the probability of drawing two consecutive aces from a deck of fifty two cards?

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1 over 3

It is 1/221. Assume that the standard deck is completely shuffled in a completely unbiased way. The probability of drawing the first ace is 4/52, since there are 4 aces in a standard deck. The probability of drawing the second ace is 3/51, since there are three aces remaining and 51 cards from which to choose. 12/52 X 51 equals 12/2652, which equals 1/221.

The probability is 1 - that is, a certainty - if you draw 51 cards without replacement.If only one card is drawn, at random, the probability is 1/26.

The probability of getting two hearts in a row: P(Getting a hearts on the first draw)*P(Getting another hearts given the first one was a hearts) The first probability is simple: there are 13 hearts in a deck of 52 cards. The probability is 13/52=1/4. The second probability is trickier: there are now 12 hearts left in a deck of 51 cards! The probability of getting another hearts is therefore 12/51=4/17. Now compute (1/4)*(4/17) and get 1/17, which is the probability of drawing two hearts from a deck of fifty-two playing cards.

There are four nines in the deck of fifty two cards. Therefore your odds are 4 out of fifty two, or one out of thirteen. (4/52 = 1/13) chances of drawing a nine. The odds, then, of not drawing a nine is 48/52, or 12/13, or about 0.9231.

Related questions

1 over 3

It is 1/221. Assume that the standard deck is completely shuffled in a completely unbiased way. The probability of drawing the first ace is 4/52, since there are 4 aces in a standard deck. The probability of drawing the second ace is 3/51, since there are three aces remaining and 51 cards from which to choose. 12/52 X 51 equals 12/2652, which equals 1/221.

Assuming there are no Joker cards the chance is one in twenty six. There are fifty two cards in a pack and only two of them are black kings.

Assuming there are no Joker cards the chance is one in twenty six. There are fifty two cards in a pack and only two of them are black kings.

The probability is 1 - that is, a certainty - if you draw 51 cards without replacement.If only one card is drawn, at random, the probability is 1/26.

The probability of getting two hearts in a row: P(Getting a hearts on the first draw)*P(Getting another hearts given the first one was a hearts) The first probability is simple: there are 13 hearts in a deck of 52 cards. The probability is 13/52=1/4. The second probability is trickier: there are now 12 hearts left in a deck of 51 cards! The probability of getting another hearts is therefore 12/51=4/17. Now compute (1/4)*(4/17) and get 1/17, which is the probability of drawing two hearts from a deck of fifty-two playing cards.

2 out of 52

The probability is one in fifty-two.

4 kings in 52 cards then 3 kings in 51 cards 4/52 * 3/51 = .00452488

1/52, or One over Fifty-Two. The odds are so because there are fifty-two cards in a deck, and there is only one Queen of Spades. The chances of you picking a Queen of Spades is One in Fifty-Two tries. If you are using jokers, 1/54, because there are 2 extra.

1/52 or one out of fifty-two

Combination of 52 things taken 2 at a time is (52 x 51)/(2 x 1)=1326. This is the total possible outcomes when drawing two cards from a deck. Combination of 4 things taken 2 at a time is (4 x 3)/(2 x 1) = 6. This is the total possible combinations of two kings (Heart/Diamond, Heart/Spade, Heart/Club, Diamond/Spade, Diamond/Club, Spade/Club). The probability, then, is 6 out of 1326, or 1/221.