If the probability of succeeding is 2%, then the probability of failing is 98%. The probability, then, of failing 75 times is 98%75, which is 22%.
Probability of success is a mathematical chance that an event will occur.
To work this out, you first need to calculate the probability of the first 8 passing, and the final 2 failing. That is 97%8x3%2 which equals 0.070536902349392649% The next step is to find out how many different ways the people can be ordered. We have 10 in total and want to order 8, so the number is 10C8, which is 45. Multiply this by the above probability and you get 3.174160605722669205% Thus the probability that 8 of the next 10 will pass is 3.17%
thirteen sixteenths.
A thirty percent chance is a low probability, so it probably won't rain, but it could.
No, it means it might, with a probability of 0.1
Probability = Chance of Success / Total Chances (Chance of Success + Chance of Failure) There are 4 aces in a 52 card deck and 48 cards that are not aces. Probability of being dealt an ace = 4 / (4 + 48) = 4/52 = .0769 or about 7.7 percent
Probability of success is a mathematical chance that an event will occur.
probably a 93 percent chance.
To work this out, you first need to calculate the probability of the first 8 passing, and the final 2 failing. That is 97%8x3%2 which equals 0.070536902349392649% The next step is to find out how many different ways the people can be ordered. We have 10 in total and want to order 8, so the number is 10C8, which is 45. Multiply this by the above probability and you get 3.174160605722669205% Thus the probability that 8 of the next 10 will pass is 3.17%
A thirty percent chance is a low probability, so it probably won't rain, but it could.
thirteen sixteenths.
Probability of D = 34%Probability of not-D = 66%Odds in favor = (chance of success)/(chance of failure) = 34/66 = 17 to 33 = almost but not quite 1 to 2.
The probability of someone living for ten years is 90%.
No, it means it might, with a probability of 0.1
18%
This is a probability question. Probabilities are calculated with this simple equation: Chances of Success / [Chances of Success + Chances of Failure (or Total Chances)] If I flip a coin, there is one chance that it will land on heads and one chance it will land on tails. If success = landing on heads, then: Chances of Success = 1 Chances of Failure = 1 Total Chances = 2 Thus the probability that a coin will land on heads on one flip is 1/2 = .5 = 50 percent. (Note that probability can never be higher than 100 percent. If you get greater than 100 you did the problem incorrectly) Your question is unclear whether you mean the probability that a coin will land on head on any of 8 flips or all of 8 flips. To calculate either you could write out all the possible outcomes of the flips (for example: heads-heads-tails-tails-heads-tails-heads-heads) but that would take forvever. Luckily, because the outcome of one coin flip does not affect the next flip you can calculate the total probability my multiplying the probabilities of each individual outcome. For example: Probability That All 8 Flips Are Heads = Prob. Flip 1 is Heads * Prob. Flip 2 is Heads * Prob. Flip 3 is Heads...and so on Since we know that the probability of getting heads on any one flips is .5: Probability That All 8 Flips Are Heads = .5 * .5 * .5 * .5 * .5 * .5 * .5 * .5 (or .58) Probability That All 8 Flips Are Heads = .00391 or .391 percent. The probability that you will flip a heads on any of flips is similar, but instead of thinking about what is the possiblity of success, it is easier to approach it in another way. The is only one case where you will not a heads on any coin toss. That is if every outcome was tails. The probability of that occurring is the same as the probability of getting a heads on every toss because the probability of getting a heads or tails on any one toss is 50 percent. (If this does not make sense redo the problem above with tails instead of heads and see if your answer changes.) However this is the probability of FAILURE not success. This is where another probability formula comes into play: Probability of Success + Probability of Failure = 1 We know the probability of failure in this case is .00391 so: Probability of Success + .00391 = 1 Probability of Success = .9961 or 99.61 percent. Therefore, the probability of flipping a heads at least once during 8 coin flips is 99.61 percent. The probability of flipping a heads every time during 8 coin flips is .391 percent.
Sounds like a 100% chance of passing school.