The probability of getting at least 1 tails is (1 - probability of getting all heads)
The probability of getting all heads (no tails) is ½ x ½ x ½ x ½ x ½ x ½ x ½ x ½ = 1/256 = 0.00390625 so the probability of getting at least ONE tails is 1-0.30390625 = 0.99609375 = 255/256
1H 1T
255/256
255/256
It is 0.375
One hundred percent it you toss the coin eight times.
Each time you toss the die the probability of rolling an even number is 3 out of 6 or 1/2. So, the probability of tossing three consecutive even numbers is (1/2)3 = 1/8 = 0.125, which is one chance in eight.
the answer is 2/13
There are eight possible outcomes: HHH, HHT, HTT, HTH, TTT, TTH, THH, THT. Of these, 3 contain two tails: HTT, TTH, and THT and the probability of getting two tails is 3/8. If the question were 'getting at least two tails' then TTT would need to be included for a probability of 4/8 or 0.5.
Is possible.
It is 0.375
The probability of getting exactly eight heads when tossing 10 coins once can be found using the binomial probability formula. Assuming a fair coin, the probability of getting a heads is 1/2. Plugging in the numbers, the probability of getting exactly eight heads is (10 choose 8) * (1/2)^8 * (1/2)^2 = 45/1024, which is approximately 0.04395.
One hundred percent it you toss the coin eight times.
Each time you toss the die the probability of rolling an even number is 3 out of 6 or 1/2. So, the probability of tossing three consecutive even numbers is (1/2)3 = 1/8 = 0.125, which is one chance in eight.
the answer is 2/13
Probability that it is one of these eight cards is 8/52. Hence the probability of not getting these eight cards is 44/52
There are eight possible outcomes: HHH, HHT, HTT, HTH, TTT, TTH, THH, THT. Of these, 3 contain two tails: HTT, TTH, and THT and the probability of getting two tails is 3/8. If the question were 'getting at least two tails' then TTT would need to be included for a probability of 4/8 or 0.5.
Looking at the total possibilities, you have eight different outcomes: TTT TTH THH HHH HHT HTT HTH THT Counting your two heads, one tails, you get a total of 3 possibilities out of 8, or 3/7
The probability of getting exactly seven tails if you flip a coin eight times is: P(7T1H) = 8∙(1/2)8 =0.03125 ≈ 3.1%
One in eight, or 12.5%.
It is approx 0.1445