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Q: What is the probability of getting four consecutive twos from tossing a fair number cube?

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It is 2/3.

Each time you toss the die the probability of rolling an even number is 3 out of 6 or 1/2. So, the probability of tossing three consecutive even numbers is (1/2)3 = 1/8 = 0.125, which is one chance in eight.

1/2 * 1/2 = 1/4 1/2= probability of landing an even number 1/2 = probability of landing a heads

The empirical probability can only be determined by carrying out the experiment a very large number of times. Otherwise it would be the theoretical probability.

Zero. Since coins land on Heads or Tails and not numbers.

fifty fifty for both.

The probability of an event is the number of favourable outcomes divided by the total number of possible outcomes. What is the total number of possible outcomes of tossing a number cube? 6 How many outcomes are favourable to the event of getting a five? 1 So the prob is 1/6 or 0.16667

the probability is 4 out of 6

The probability of tossing an odd number (assumed on a die) is 3 in 6 or 1 in 2. The probability of tossing a tail (assumed on a coin) is 1 in 2. Since these are unrelated events, and the question said "and", simply multiply the probabilities to get 1 in 4.

In a large enough number of tosses, it is a certainty (probability = 1). In only the first three tosses, it is (0.5)3 = 0.125

It is 0.375

First probability of getting 2 is one in six: 1/6probability of getting no greater than 4 is two chances in six (must be a 5 or 6): 2/6=1/3so probability = 1/6*1/3= 1/18.

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