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The following figures can only lead to the sum of 10. So the permuatation of each combination is as follows.

1 1 1 1 6 = 5

1 1 1 2 5 = 20

1 1 1 3 4 = 20

1 1 2 2 4 = 30

1 1 2 3 3 = 30

1 2 2 2 3 = 20

2 2 2 2 2 = 1

That is the number of ways to get a sum of 10 is 126 and the total of number of distinct throws that can be available are (6 to the power 5) 7776 and the required probability is 126/7776 = 0.016203703703703703703703703703704.

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Q: What is the probability of obtaining a sum of 10 in a single throw with 5 dice?
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