Well, you have a 6-4, or 4-6 and a 5-5, that's the only rolls that will role a ten. Out of 6*6=36 possible rolls. so, 3/36.
1/3
3 out of 9
The composite numbers are 4 and 6; that is 2/6 of the numbers available. Therefore the odds on rolling such a number are "two out of 6" = 1/3 = 33.333%The 3 in that answer is recurring.Since the total of all probabilities which might occur in one event is 1.0 or 1 or 100%, it follows that the probability of not throwing a composite number is 4/6 = 2/3 = 66.66666666666666(recurring)%
If a fair die is thrown often enough, the probability is 1.For the first three throws of a fair die, the probability is 1/216.If a fair die is thrown often enough, the probability is 1.For the first three throws of a fair die, the probability is 1/216.If a fair die is thrown often enough, the probability is 1.For the first three throws of a fair die, the probability is 1/216.If a fair die is thrown often enough, the probability is 1.For the first three throws of a fair die, the probability is 1/216.
A die normally has 6 sides numbered 1 through 6. The probability of you landing on ANY number is 1:6, or you have a 1 in 6 chance of landing a 3.
1/3
the probability is 2/6 or 1/3
This is the same as 1 minus the probability that neither of them are greater than three. This is 1, minus the probability of getting greater than three, squared. Rolling higher than three has a 1/2 probability, so: P(at least one greater than 3) = 1 - (1/2)2 = 1 - 1/4 = 3/4
When a fair die is thrown the probability that a prime number will occur is 2:1
If two dice (not dices!) are thrown then the probability that you get an even number on one die is 27/36 = 3/4
in the equation system f/d = p where f is the number of sides of the rolled polyhedron which contain a number of spots that can be represented by a positive integer not divisible by 2 and d represents the total number of faces of the polyhedron which can, in the rest position, face upward, the variable p represents the probability of rolling an odd number. from this it can also be derived that the probability p of rolling an even number can be represented by (d-f)/d.
1 out of 6
When you throw a fair dice you have an equal possibility of getting 1, 2, 3, 4, 5 or 6. If you want to get a number greater than 4 this means you want 5 or 6: the probability is 2/6, which can be simplified to 1/3.
There are six possible outcomes of rolling a six sided die.However, only two of these (1 and 2) are favorable.So, the probability of rolling less than three is 2/6 = 1/3.
It is 11/18.
3 out of 9
The composite numbers are 4 and 6; that is 2/6 of the numbers available. Therefore the odds on rolling such a number are "two out of 6" = 1/3 = 33.333%The 3 in that answer is recurring.Since the total of all probabilities which might occur in one event is 1.0 or 1 or 100%, it follows that the probability of not throwing a composite number is 4/6 = 2/3 = 66.66666666666666(recurring)%