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Q: What is the probability of the following events P(b and an even number)?

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If the probability of a event is zero, then the event cannot occur. Therefore, if the probability of an even number is zero, then the probability of an odd number is one.

The probability is 1/2.

depends on how many of the even numbers you have

50%

The probability of event A is the number of ways event A can occur divided by the total number of possible outcomes. For example, the number of ways you can role a single die is 6, the number of ways to get an even number (2,4, or 6) is 3. So the probability of an even number is 3/6 or .5

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If the probability of a event is zero, then the event cannot occur. Therefore, if the probability of an even number is zero, then the probability of an odd number is one.

The probability is 1/2.

50%

In base ten, and with no whacky assumptions, the probability that 11 is even is zero.

The probability of rolling an even number on a die is 3 in 6 or 1 in 2. The probability of rolling a prime on a die is 3 in 6 or 1 in 2, but one of those primes is also even. Simply add the probabilities and you find that the probability of rolling an even number or a prime on a die is 5 in 6.

The addition rule of probability states that the probability that one or the other will happen is the probability of one plus the probability of the other. This rule only applies to mutually exclusive events. For example, the probability that a dice roll will be a 3 is 1/6. The probability that the dice roll will be even is 1/2. These are mutually exclusive events as the dice cannot be both 3 and even. Thus the probability of the dice roll coming up either a 3, or even, is 1/2 + 1/6 = 2/3.

depends on how many of the even numbers you have

Possible outcomes of one roll = 6.Probability of an even number on one roll = 3/6 = 0.5 .Probability of an even number on the second roll = 0.5 .Probability of an even number on the third roll = 0.5 .Probability of an even number on all three rolls = (0.5 x 0.5 x 0.5) = 0.125 = 1/8The probability of at least one odd number is the probability of not gettingan even number on all 3 rolls. That's (1 - 1/8) = 7/8 or 0.875 or 87.5% .

Probability zero. If both dice have the same number, then the result will be even. If both dies are odd (as in the case of 5) then the sum is even. If both dies are even, the sum is also even. The only way to get an odd sum is to have one die have an odd number and the other die have an even number. That will happen 50% of the time.The probability of both dice showing 5 is 1/36. But the two events will never happen at the same time.

The probability of getting an even number on at least one of the 3 rolls is 7/8.

The question asks "What is the probability of rolling either an even number on the first roll or a 1 on the second roll?" These events are independent from each other as the outcome of the second roll is not affected by the outcome of the first roll. However, these events are non-mutually exclusive, meaning that these events can both occur at the same time.The probability of rolling an even number on the first roll is 3/6 because 2, 4, and 6 are even numbers and a six-sided die has six possible numbers.The probability of rolling a 1 on the second roll is 1/6.If these two probabilities are added together, we will have "double counted" the event where an even number is rolled on the first roll and a 1 is rolled on the second roll. To correct for this, we must subtract the probability of both events occurring.The probability that both events occur is 3/36, because 3/6 * 1/6 = 3/36.Now, the probability of rolling either an even number on the first roll or a 1 on the second roll is:3/6 + 1/6 - 3/36= 18/36 + 6/36 - 3/36= 21/36= 7/12

your set of even number x = {2,4,6}, which tells you that 3 out the 6 sides are even. Your probability is 3/6 = 1/2