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This equates to throwing ten fives. The probability of throwing one five with one die is (of course) one sixth. We multiply the ten independent probabilities to obtain the overall probability, about one in sixty million: (1/6)10 = 1/610 = 1 / 60466176

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Q: What is the probability of throwing a hard ten 5 times in a row Using 2 dice with 6 sides a hard ten meaning both dice show a five although other combintions will equal 10.?
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