Your question is a bit difficult to understand. I will rephrase it as follows:
What is the probability of getting a head if a coin is flipped once?
p = 0.5
What is the probability of getting 2 heads if a coin is flipped twice =
The possible events are HT, TH, HH, TT amd all are equally likely. So the probability of HH is 0.25.
What is the probability of getting at least on head if the coin is flipped twice.
Of the possible events listed above, HT, TH and HH would satisfy the condition of one or more heads, so the probability is 3 x 0.25 = 0.75 or 3/4.
Also, since the probability of TT is 0.25, and the probability of all events must sum to 1, then we calculate the probability of one or more heads to be 1-0.25 = 0.75
The probability of flipping a quarter and getting heads is 1 in 2. the probability of rolling a die and getting 6 is 1 in 6.
The probability of flipping a coin 3 times and getting 3 heads is 1/2
The probability is 0.375
The probability of this is 50%. 2/4
The probabilty of you flipping 3 coins and getting all heads or tails is 0.125 or 1/8.
There are 8 permutations of flipping a coin 3 times, or of flipping 3 coins one time. They are, with the permutations of two heads bolded...TTTTTHTHTTHHHTTHTHHHTHHH... thus, the probability of flipping a coin 3 times and getting 2 heads is 3 in 8, or 0.375.
The probability of NOT getting heads is (1/2)4=1/16 Therefore the probability of getting heads is 1-1/16=15/16
The probability is 25%. The probability of flipping a coin once and getting heads is 50%. In your example, you get heads twice -- over the course of 2 flips. So there are two 50% probabilities that you need to combine to get the probability for getting two heads in two flips. So turn 50% into a decimal --> 0.5 Multiply the two 50% probabilities together --> 0.5 x 0.5 = 0.25. Therefore, 0.25 or 25% is the probability of flipping a coin twice and getting heads both times.
0.54 or 0.0625 or 1/16.