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Q: What is the probability that a 3-digit number has an even digit in the hundreds place?
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What is the answer for you are a 3digit odd number your tens digit is 1 less than your hundreds digit but 2 more than your ones digitThe sum of your digit is 20 Who are you?

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The digit in the hundreds place in the number 463 is the digit 4.


In a 3 digit number the tens digit is 4 times the hundreds digit The hundreds digit is not 1 The ones digit is 5 What is the number?

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The probability that a number selected from random between 100 and 999 both inclusive will not contatin the digit 7?

For me I think it is conceptually easier to think about the probability that the number will contain the digit seven (and the probability that it does not contain the digit 7 is simply one minus the probability that it does). P(number will contain 7) = P(number is in the seven hundreds) + P(number is not in seven hundreds)*[P(number is in the X hundred seventies)+P(number is not in the X hundred seventies)*P(number ends in seven)] So essentially I am considering all of the numbers in the range that start with seven (i.e., are in the seven hundreds), then all of the numbers in the range that aren't in the seven hundreds but have a 7 in the tens place (i.e., the 170s, 270s, etc., and finally all the numbers that don't have a 7 in the hundred or tens place, but that end in 7). Plugging the numbers into my formula above, I get (100/900)+(800/900)*((10/100)+(90/100)(1/10)) = 7/25 is probability that the number does contain a 7, and 1-(7/25)=18/25 is probability that it does not.