The probability the shooter makes both shots is .7 * .7 = .49, and the probability of making neither is .3 * .3 = .09. So the probability of making exactly 1 out of 2 is 1 - .49 - .9 = .42, or 42 percent.
42% is the top
With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.
The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.The probability of getting an odd number in a single throw of a fair die (not dice!) is 1/2.
When you throw a die, there are six possibilities. The probability of a number from 1 to 6 is 1/6. This is classical probability. Compare this with empirical probability. If you throw a die 100 times and obtain 30 sixes, the probability of obtaining a 6 is 30/100 or 0.3. Empirical probabilities change whereas classical probability doesn't.
In basketball, the free throw is an important shot; it can highly increase points for a team if the player should make the shot. In 2010, Stephen Curry was the NBA player who has the highest percentage of free throw shots.
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You want the probability of miss and miss and miss which is .67 * .67 * .67 = 0.301.
We'll if they are 89% it's pretty high
There is a 58% chance they are going to miss.
The probability of four out of six shots is the probability of four successes, times the probability of two failures, times the number of permutations of successes and failures: P(four out of six free throws) = 15 * (2/5)4 * (3/5)2 = (15 * 16 * 9) / (625 * 25) = 432 / 3125
If she is a 41% shooter she will probably score a goal 41 times out of a hundred, but she will probably miss the other 59 times out of a hundred. So the probability that she will miss is 59 out of 100 = 59% = 0.59
10.56% The probability that he misses his first shot is 12%. The probability that he makes the second shot is 88%. The probability of missing the first shot and making the second shot is 12% * 88%, or 0.12*0.88*100.
Convert to a fraction, then convert to a decimal by dividing the numerator by the denominator. 0.00875 of per shots
With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.With a single throw of a normal die, the probability is 0.
There is a 10 percent chance that you are gonna throw a 1.
Ben Wallace
yes
No, not that I ever heard of. It maybe if you are talking to the free throw shooter.