P(at least one heart out of two cards drawn) = 1 - P(neither being a heart)
= 1 - (39/52)(38/51) = 1 - (2 * 3 * 13 * 19)/(2 * 2 * 3 * 13 * 17) = 1 - 19/34
= (34 - 19)/34 = 15/34
P(at least one heart out of two cards drawn) = 15/34
The solution depends on whether the "or" is inclusive or exclusive.
P(heart or six, inclusive) = P(heart) + P(six) - P(six of hearts) = 13/52 + 4/52 - 1/52 = 16/52 or 4/13
P(heart or six, exclusive) = P(heart) + P(six) - 2P(six of hearts) = 13/52 + 4/52 - 2/52 = 15/52
16 out of 52 or about 30.77 percent.
4/13
The answer depends on how many cards are drawn, whether or not at random, with or without replacement. The probability for a single card, drawn at random, from a normal deck of playing cards is 2/13.The answer depends on how many cards are drawn, whether or not at random, with or without replacement. The probability for a single card, drawn at random, from a normal deck of playing cards is 2/13.The answer depends on how many cards are drawn, whether or not at random, with or without replacement. The probability for a single card, drawn at random, from a normal deck of playing cards is 2/13.The answer depends on how many cards are drawn, whether or not at random, with or without replacement. The probability for a single card, drawn at random, from a normal deck of playing cards is 2/13.
5/9
The answer depends on how many cards are drawn, whether or not at random, from an ordinary deck of cards, with or without replacement.For a single card, drawn at random from an ordinary deck of playing cards, the probability is 2/13.The answer depends on how many cards are drawn, whether or not at random, from an ordinary deck of cards, with or without replacement.For a single card, drawn at random from an ordinary deck of playing cards, the probability is 2/13.The answer depends on how many cards are drawn, whether or not at random, from an ordinary deck of cards, with or without replacement.For a single card, drawn at random from an ordinary deck of playing cards, the probability is 2/13.The answer depends on how many cards are drawn, whether or not at random, from an ordinary deck of cards, with or without replacement.For a single card, drawn at random from an ordinary deck of playing cards, the probability is 2/13.
The probability is 1 - that is, a certainty - if you draw 51 cards without replacement.If only one card is drawn, at random, the probability is 1/26.
It is 2/13.
The probability of getting the queen of hearts is 1 in 52, or about 0.01923. The probability of getting any queen is 4 in 52, or about 0.07692. The probability of getting any heart is 13 in 52, or exactly 0.25.
number of cards in a deck=52 cards drawn =52 n(s)=52nCr2=1326 number of cards that are queen=4 number of cards that are king=4 n(A)=4nCr1*4nCr1 =4*4 P(A)=n(A)/n(s)=16/1326=6/663
For a single random choice from a standard deck, the probability is 1/13.For a single random choice from a standard deck, the probability is 1/13.For a single random choice from a standard deck, the probability is 1/13.For a single random choice from a standard deck, the probability is 1/13.
The probability of drawing the queen of hearts is 1 in 52, or about 0.01923.
1/25
If 1 queen was drawn out of the 52 card deck without replacement, the probability of choosing a queen on the 2nd draw is 3/51 or 1/17.