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P(at least one heart out of two cards drawn) = 1 - P(neither being a heart)

= 1 - (39/52)(38/51) = 1 - (2 * 3 * 13 * 19)/(2 * 2 * 3 * 13 * 17) = 1 - 19/34

= (34 - 19)/34 = 15/34

P(at least one heart out of two cards drawn) = 15/34

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13y ago
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13y ago

The solution depends on whether the "or" is inclusive or exclusive.

P(heart or six, inclusive) = P(heart) + P(six) - P(six of hearts) = 13/52 + 4/52 - 1/52 = 16/52 or 4/13

P(heart or six, exclusive) = P(heart) + P(six) - 2P(six of hearts) = 13/52 + 4/52 - 2/52 = 15/52

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13y ago

16 out of 52 or about 30.77 percent.

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Q: What is the probability that a card drawn at random is a queen or a heart?
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