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I am assuming that you are not replacing the cards in the deck after each draw.

The probability of drawing no clubs = (52-13)/52*(51-13)/51*(50-13)/50*(49-13)/49

p= 39/52*38/51*37/50*36/49 ~= 0.3038 = 30.38%

The probability of drawing at least one club = 1-0.3038=.6962 = 69.62%

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14y ago
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11y ago

(13*12*11*10)/(52*51*50*49) which works out at11 in 4165

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about 0.26%

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13y ago

13/204

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13y ago

1 in 52

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Q: If you are dealt 4 cards from a shuffled deck of 52 cards what is the probability that all 4 cards are clubs?
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