The probability that a parent carrying a dominant trait will pass that trait on is a 50% chance with each pregnancy
25%
There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.There is not enough information on the propensity for the parents to have a child of either gender and so it is necessary to assume that the probability of the gender of the next child is independent of the genders of preceding children. In that case the probability of the next child being a girl is 1/2.
The chance of the child having schizophrenia when both parents have schizophrenia is about 37%. There is no data available for other combinations of illnesses, for example if one parent has schizoaffective disorder and the other has schizophrenia.
0.1%
50%
50%
No probability. Neither parent has an "A" for the child to inherit to make an "AB".
The dominant parent is most likely homozygous dominant, and the recessive parent has only the homozygous genotype. So the dominant parent can pass on only dominant alleles for this trait, and the recessive parent can pass on only recessive alleles for this trait. So all of the offspring would be heterozygous and have the dominant phenotype.
Yes. It does not matter if the mother or father does not have a characteristic that the child has possessed
Transmitted by a dominant gene. If that gene is inherited from either parent, the offspring will develop HD. If the gene is NOT inherited, then the offspring will not have HD- AND cannot pass the gene to their offspring.
A child gets half of its DNA from each parent. This is why you can see characteristics of both parents in a child. --truckbroker-- More importantly, some traits are recessive in the parent. Or dominant in a dominant recessive trait. In which they may skip generations.
It depends on the two alleles the man carries; if he is carrying HH- it is a 100% chance, because HD is autosomal dominant. If his allele is Hh, it is a 50% chance.
No, sometimes there are instances of "codominance", where two dominant traits are expressed equally. This occurs in the human body for example, with A and B type blood. An A parent and a B parent, can produce an AB type child. Both types A and B are dominant to O type blood, however they can coexist together.
No. A and B are dominant blood types and O is recessive. A parent with blood type AB can only donate a dominant A or dominant B. A child with blood type O would need to come from parents with one of the following combinations: A-A, A-B, A-O, B-O, O-O
Could be any type, we all get our blood groups from our parents or even our grandparents so, if your child is not B positve, your child will have the same blood group as one of its four grandparents.
Assuming that each parent is a carrier for cystic fibrosis (has the genotype Ff), the probability that their second child will develop cystic fibrosis is one fourth. The probability doesn't change with the number of children they have. For each pregnancy, the chance that the child will have cystic fibrosis (have the genotype ff) is exactly the same.
No, the blood types a and b are dominant alleles and would mask the recessive o blood type.