It is 0.5
1/2 or 50%
1/5 1 out of 5.
1/2 or 0.5
because there are only 2 sides. It can land on one of those 2 sides.
One out of every four flips
There is a 50% chance that it will land on heads each toss. You need to clarify the question: do you mean what is the probability that it will land on heads at least once, exactly once, all five times?
The probability of tossing a coin twice and getting tails both times is 1 in 4, or 25%. If you have already tossed a coin and had it land on tails, the probability that it will land on tails again the next time you toss it is 50%.
The expected value is the number of tosses times the probability of tails, so: E(number of tails) = 52 * 1/2 = 52/2 = 26
The probability of a fair coin to land head is 1/2. Since for 4 flips it must land heads each time, the probability of 4 heads is 1/2 * 1/2 * 1/2 * 1/2 = 1/16.
It is 1/3
If a standard number cube or die is rolled, the probability that a 4 does not land face up is five out of six, or (six minus one) out of six.
I believe it's 4/8 or 1/2 and the probability of the even number is 4/8 also.
There are two sides on a coin. The odds are 50:100, or 1:2. Half the time the coin SHOULD land on heads.
0.5*0.5*0.5 = 0.125 or 1/2*1/2*1/2 = 1/8
(1/2) * (1/6) = 1/12
Total number of possible outcomes = 6Number of successful outcomes = 2Probability = 2/6 = 1/3 = [ 33 and 1/3rd ] percent.
You roll it many times. The probability that it lands on a six is the number of times that it lands on a six divided by the number of times the die has been rolled.
The probability is 3/8.
It is the proportion of the spinner's perimeter that is occupied by the section (or sections) with a value of 1.
Zero. Since coins land on Heads or Tails and not numbers.
That would depend on how many numbers are on the spinner and the cube. The more numbers there are, the less likely it is that they would both land an any given number.