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What is the probability that the first two flips will both be heads and the third flip will be tails if you flip three fair coins?
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If You flip 9 fair coins Amazingly the first 8 flips all come up heads What is the probability that the final flip will be a head too?
1/2 apex It does not matter what each prior flip's result was. Each flip has a probability of 0.5 heads or tails. Coins do not have "memory".
What is the probability of tossing four coins and getting four heads if the first two tosses are heads?
The conditional probability is 1/4.
What is the probability of tossing seven coins and getting 6 heads?
The probability of getting only one tails is (1/2)7. With seven permutations of which flip is the tails, this gives a probability of: P(six heads in seven flips) = 7*(1/2)7 = 7/128
If you flipped two coins what is the probability that the first coin is heads?
The probability is always 50/50 even if you flipped 100 or 1000000 coins.
What is the probability of exactly three heads in four flips of a coin given at least two are heads?
If you know that two of the four are already heads, then all you need to find isthe probability of exactly one heads in the last two flips.Number of possible outcomes of one flip of one coin = 2Number of possible outcomes in two flips = 4Number of the four outcomes that include a single heads = 2.Probability of a single heads in the last two flips = 2/4 = 50%.
If You flip 9 fair coins Amazingly the first 8 flips all come up heads What is the probability that the final flip will be a head too?
1/2 apex It does not matter what each prior flip's result was. Each flip has a probability of 0.5 heads or tails. Coins do not have "memory".
What is the probability of tossing four coins and getting four heads if the first two tosses are heads?
The conditional probability is 1/4.
What is the probability of obtaining exactly six heads in seven flips of a coin given that at least one is a head?
The requirement that one coin is a head is superfluous and does not matter. The simplified question is "what is the probability of obtaining exactly six heads in seven flips of a coin?"... There are 128 permutations (27) of seven coins, or seven flips of one coin. Of these, there are seven permutations where there are exactly six heads, i.e. where there is only one tail. The probability, then, of tossing six heads in seven coin tosses is 7 in 128, or 0.0546875.
What is the probability that in four coin flips you get at least 2 heads?
50%
If you flipped two coins what is the probability that the first coin is heads?
The probability is always 50/50 even if you flipped 100 or 1000000 coins.
What is the probability of tossing seven coins and getting 6 heads?
The probability of getting only one tails is (1/2)7. With seven permutations of which flip is the tails, this gives a probability of: P(six heads in seven flips) = 7*(1/2)7 = 7/128
Two coins are tossed What is the probability of both coins are heads?
The probability that both coins are heads is the probability of one coin landing heads multiplied by the probability of the second coin landing heads: (.5) * (.5) = .25 or (1/2) * (1/2) = 1/4
What is the probability of getting 2 heads when 2 coins are tossed?
The probability of tossing two heads in two coins is 0.25.
What is the probability of 3 heads and 2 tails on five flips of a coin?
It is 0.3125
Maria flips a dime four times What is the probability that she will get at least two heads?
It is 0.6875
What is the probability of exactly three heads in four flips of a coin given at least two are heads?
If you know that two of the four are already heads, then all you need to find isthe probability of exactly one heads in the last two flips.Number of possible outcomes of one flip of one coin = 2Number of possible outcomes in two flips = 4Number of the four outcomes that include a single heads = 2.Probability of a single heads in the last two flips = 2/4 = 50%.
What is the probability of flipping three coins and all of them land up on heads?
The probability of the first coin landing heads is half (or 1/2). Similarly, the probability of the second and third coins landing heads are also 1/2 in each case. Therefore, the probability of having three heads is: (1/2)(1/2)(1/2) = (1/8)
