0
What else can I help you with?
What is the probability that a cross between a hybrid pea plant with round seeds and one with wrinkled seeds will produce offspring with wrinkled seeds?
The probability that an offspring will have wrinkled seeds is 2 in 4 or 50%
What is the probability that two heterozygous parents would have an offspring that produced round seeds from Mendel?
When both parents are heterozygous for seed shape (Rr, where R is the allele for round seeds and r is the allele for wrinkled seeds), the probability of producing an offspring with round seeds can be determined using a Punnett square. The possible genotypes are RR, Rr, Rr, and rr. Thus, there are three combinations (RR and Rr) that result in round seeds out of four total combinations. Therefore, the probability of having an offspring with round seeds is 3 out of 4, or 75%.
What was the probability that two heterozygous parents would have an offspring that produced rounds seeds?
3:4 or 75%
What is the probability that an offspring will be white?
The question depends on what the offspring is of!
What is the probability that two heterozygous parents would have an offspring that produced round seeds?
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
What is the probability that a cross between a hybrid pea plant with round seeds and one with wrinkled seeds will produce offspring with wrinkled seeds?
The probability that an offspring will have wrinkled seeds is 2 in 4 or 50%
What is probability that two heterozygous parents would have an offspring that produced round seeds?
It is a 75% chance that the seeds will be round.
What is the probability that two heterozygous parents would have an offspring that produced round seeds from Mendel?
When both parents are heterozygous for seed shape (Rr, where R is the allele for round seeds and r is the allele for wrinkled seeds), the probability of producing an offspring with round seeds can be determined using a Punnett square. The possible genotypes are RR, Rr, Rr, and rr. Thus, there are three combinations (RR and Rr) that result in round seeds out of four total combinations. Therefore, the probability of having an offspring with round seeds is 3 out of 4, or 75%.
What was the probability that two heterozygous parents would have an offspring that produced rounds seeds?
3:4 or 75%
What is the probability that a offspring will have wrinkled seeds?
R represents the dominant round allele, and rrepresents the recessive wrinkled allele. :D
What was the probability that two heterozygous parents would have an offspring that produced round seeds?
If both parents are heterozygous for seed shape (Rr), their offspring would have a 75% chance of producing round seeds (3 out of 4 possible combinations), assuming round seeds (R) are dominant over wrinkled seeds (r).
What is the probability that an offspring will be white?
The question depends on what the offspring is of!
What is the probability of a hybrid offspring in a cross between two hybrid plants?
The hybrid is the offspring so the probability is 1.
What is probability that wto heterozygous parents would have an offspring that produced round seeds?
75% because the recessive and dominant genes are corresponding and in a Punnett square it takes over.
What is the probability that two heterozygous parents would have an offspring that produced round seeds?
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
What is the Probability of having a female offspring?
50%
What is the probability the human offspring will be female?
51%..
