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What is the probability to get tail at least once when 6 coins are tossed simultaneously?
Wiki User
∙ 13y ago
Number of possible outcomes of one coin = 2
Number of possible outcomes of six coins = 2 x 2 x 2 x 2 x 2 x 2 = 64
Number of possible outcomes with six heads = 1
Probability of six heads = 1/64
Probability of not six heads = at least one tails = 63/64 = 98.4375%
Wiki User
∙ 13y ago
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What is the probability that at least one coin will be tails?
The answer depends on how many coins were tossed.
You toss 3 coins what is the probability that at least 1 tail is tossed?
1/6
When tossing 4 coins simultaneously find the probability that at least 1 head is showing?
It is 15/16.
When tossing 5 coins simultaneously what is the probability that at least 1 head is showing?
Probability of no heads = (0.5)^5 = 0.03125Probability of at least one head = 1 - probability of no heads = 1 - 0.03125 = 0.96875
When tossing 5 coins simultaneously can you find the probability that at least 1 head is showing?
Probability not at least 1 head showing is when all 5 coins are tails: (1/2)5=1/32 Therefore probability at least 1 head is showing is 1-1/32=31/32
If 3 coins are tossed simultaneously the probability of getting at least 1head is?
3/8
What is the probability that at least one coin will be tails?
The answer depends on how many coins were tossed.
You toss 3 coins what is the probability that at least 1 tail is tossed?
1/6
When tossing 4 coins simultaneously find the probability that at least 1 head is showing?
It is 15/16.
When tossing 5 coins simultaneously what is the probability that at least 1 head is showing?
Probability of no heads = (0.5)^5 = 0.03125Probability of at least one head = 1 - probability of no heads = 1 - 0.03125 = 0.96875
If nine fair coins are tossed what is the probability of obtaining at least one head and at least one tail using the complement formula?
255/256 (complement formula)
When tossing 5 coins simultaneously can you find the probability that at least 1 head is showing?
Probability not at least 1 head showing is when all 5 coins are tails: (1/2)5=1/32 Therefore probability at least 1 head is showing is 1-1/32=31/32
When 2 coins are tossed simultaneously what is probabiliy of getting atleast two heads?
At least two heads with two coins? You can't get more.There are 4 different outcomes:tail-tail, head-tail, tail-head and head-head.You can use one out of four - which gives us the probability 1/4 = 0.25 = 25%
When tossing 3 coins simultaneously find the probability that at least 1 head is showing?
No matter how many coins are thrown, the possibility of having AT LEAST ONE 'head' is 50%. This changes if you specify the number of 'heads' that must be shown.
When tossing 5 coins simultaneously find the probability that at least 1 head is showing.?
This is easiest to solve by working out the probability that no heads show and subtracting this from 1 to give the probability that at least one head shows: Assuming unbiased coins which won't land and stay on their edge, the probability of head = probability of tail = ½ → probability no heads = probability 5 tails = ½^5 = 1/32 → probability of at least one head = 1 - 1/32 = 31/32 = 0.96875 = 96.875 % = 96 7/8 %
What is the probability of getting at least one head if 2 quarters were tossed?
It is 0.75
A coin is tossed 10 times. What is the probability of getting at least one head?
Assuming that it is a fair coin, the probability is 0.9990
