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Q: What is the product of the prime factors of 36?

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The prime factors of 36 are 2, 2, 3, and 3, so their product is 36. The distinct prime factors of 36 are 2 and 3, so their product is 6.

As a product of its prime factors: 2*2*3*3 = 36

As a product of its prime factors: 2*2*3*3 = 36 or as 22*32 = 36 As a product of its prime factors: 3*13 = 39

As a product of its prime factors in exponents: 22*32 = 36

As a product of its prime factors it is: 223*3 = 36

6

As a product of its prime factors: 2*2*3*3 = 36

As a product of its prime factors: 2*2*3*3 = 36

As a product of its prime factors in exponents: 22*32 = 36

As a product of its prime factors: 2*2*3*3 = 36

As a product of its prime factors: 2*2*3*3 = 36

36 as a product of its prime factors is 2 x 2 x 3 x 3. Their total is 10. 36 as a product of factors that total 13 is 4 x 9

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