Q: What is the product of the prime factors of 80?

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Prime factorization of 540 = 2x2x3x3x3x5 Prime factorization of 80 = 2x2x2x2x5

2*2*2*2*5

The product of the prime factors of any number is equal to the number itself. Therefore, the product of the prime factors of 350 is 350.

The product of the prime factors of a number is the number itself.

As a product of its prime factors: 225*5 = 100

Related questions

As a product of its prime factors in exponents: 24*5 = 80

The prime factors of 80 are 2,2,2,2,5.The product is 2x2x2x2x5, which is 80.

As a product of its prime factors: 2*2*2*2*5 = 80 As a product of its prime factors: 2*2*5*5 = 100

Prime factorization of 540 = 2x2x3x3x3x5 Prime factorization of 80 = 2x2x2x2x5

It is: 2*2*2*2*5 = 80

2*2*2*2*5

The product of factors is called the product.The product of prime factors is called the prime factorization.

2 x 2 x 2 x 2 x 5 = 80

Multiply prime numbers or prime factors to find their product.

As a product of its prime factors: 2*5*7 = 70

The prime factors of 80 are 2 and 5. For them to be common, they need to be compared to another set of prime factors.

The product of the prime factors of any number is equal to the number itself. Therefore, the product of the prime factors of 350 is 350.