The question, as posted, is meaningless. Make up your mind as to whether you a re interested in product or sum.
5+y=12
In an addition sum, if the missing number is the first number, for example, x + 5 = 10, then to find x, perform the sum 10 - 5, producing the solution x = 5. In a subtraction sum, if the missing number is the second number, for example, 7 - y = 4, then to find y, perform the sum 7 - 4 = 3, production the solution y = 3.
x*(y+z) = x*y + x*z This is the distributive property of multiplication over addition.
x = 10, y = 25
x + y = 5xy=41 and 4 works. ■
The sum of x and y decreased by their product is (x + y)- xy.
5+y=12
5
In an addition sum, if the missing number is the first number, for example, x + 5 = 10, then to find x, perform the sum 10 - 5, producing the solution x = 5. In a subtraction sum, if the missing number is the second number, for example, 7 - y = 4, then to find y, perform the sum 7 - 4 = 3, production the solution y = 3.
x*(y+z) = x*y + x*z This is the distributive property of multiplication over addition.
x = 10, y = 25
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
x + y = 5xy=41 and 4 works. ■
We will get two values of y . One is y=6 and another is y=13
17
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
Let x = one number = 2 or 2.5 Let y = the other number = 2.5 or 2 (x)(y)=5 x+y=4.5 y=4.5-x (x)(y)=5 (x)(4.5-x)=5 4.5x-x^2-5=0 I used the quadratic formula to get x. x=2 or x=2.5 (x)(y)=5 (2)(y)=5 y=5/2 y=2.5 (x)(y)=5 (2.5)(y)=5 y=5/2.5 y=2