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The equation must have roots of x = -1 and x = 5
So: x + 1 = 0 and x - 5 = 0
Therefore: (x + 1)(x - 5) = 0
Expanding the brackets gives the equation:
x2 - 4x - 5 = 0
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What is the area of the square whose side measures 2x-5 cm?
It is: (2x-5)(2x-5) = 2.5 square cm when solved as a quadratic equation
What is 10x squared -29x plus 10 equals 0 when factored and its solutions?
Equation: 10x^2 -29x +10 = 0 When factored: (2x-5)(5x-2) = 0 Its solutions: x = 5/2 or x = 2/5
What is the equation of the line that goes through 3 1 and is parallel to the line 3x plus 5y equals 6?
Known equation: 3x+5y = 6 or y = -3/5x +6/5 Slope of equation: -3/5 Slope of parallel equation: -3/5 Parallel equation: y-1 = -3/5(x-3) => 5y = -3x+14 Parallel equation in its general form: 3x+5y-14 = 0
The length of rectangle is 5 less than twice the width The perimeter of the rectangle is 80. Find the dimensions of the rectangle?
L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15 L= Length W= Width P= Perimeter Equation 1: L= 2W-5 Equation 2: 2L+2W=P=80 Then, From Equation 2, Solve the second equation for 2W. 2L + 2W= 80 2W = 80 - 2L From Equation 1, Substitute 80-2L for 2W in the first equation. This gives the equation one variable, which earlier algebra work.L=(80-2L)-5 L=80-2L-5 2L + L= 80 - 5 3L= 75 L=25 Now, substitute 25 for L in either equation and solve for w. From Equation 1 25 = 2W - 5 5 +25 = 2W30 = 2W 30 / 2 =W 15=W The solution is Lengh = 25 Width = 15
How do you find the standard form of a linear equation knowing only the y intercept and the slope IE A line has a slope of 5 over 3 and a y intercept of 1 over 2 State the equation in standard form?
Since we know the slope, m = 5/3, and the y-intercept 1/2, we arw able to write the equation of the line in the slope-intercept form, y = mx + b, so we have y = (5/3)x + 1/2.The standard form of the equation of the line is Ax + By = C.y = (5/3)x + 1/2y - y - 1/2 = (5/3)x - y + 1/2 - 1/2-1/2 = (5/3)x - y or(5/3)x - y = -1/2Thus, the standard form, Ax + By = C, of the equation of the line is (5/3)x - y = -1/2.
What quadratic equation has solutions of 5 and 7?
x2 - 12x + 35
What is the discriminant for x2-4x-5 equals 0?
The discriminant is 36 which means the quadratic equation has two solutions which are 5 and -1
Write a quadratic equation having the given numbers as solutions negative 5 and negative 1?
(x + 5) (x + 1) = 0x2 + 6x + 5 = 0
Find the quadratic equation if the following solutions are 3 and 5?
x2 - 8x + 15
2x square plus 11x plus 5 equals?
The given expression is a quadratic equation. To find its solutions, we can either factor the equation or use the quadratic formula. However, without an equation to solve or any context, it is not possible to provide a numeric answer.
The Square of a number is 5 more than 4 times the number. Find the number that makes the sentence true.?
This is a quadratic equation which will have two solutions: X2 = 4x+5 Rearrange the equation: x2-4x-5 = 0 Factor the equation: (x+1)(x-5) = 0 So the solutions are: x = -1 or x = 5
How many real solutions are there for the equation x2 plus 3x plus 5 equals 0?
There are no real solutions because the discriminant of the quadratic equation is less than zero.
Choose the quadratic equation with a leading coefficient of 1 that has as solutions -2 plus 3 square root 5 and -2 -3 square root 5?
x2 + 4x = 41
What is y squared minus 4y minus 5?
It is a quadratic equation in the form of y2-4y-5 = 0 and will have two solutions: When factorised: (y-5)(y+1) = 0 Therefore: y = 5 or y = -1
How do you translate Quadratic equation?
Translate to what? I assume you need help interpreting it. The quadratic equation is used to solve the quadratic polynomial, ax2 + bx + c = 0, where a, b, and c can be any number. For example, if you need to solve the equation x2 = 5 + 2x, you first convert it into the standard form mentioned above: x2 - 2x - 5 = 0. Now find the coefficients, a, b, and c. In this case, a = 1, b = -2, c = -5. Finally, you replace these coefficients in the quadratic equation. The "plus-minus" sign simply means that the quadratic equation is a shortcut for two equations - one in which you add, the other in which you subtract, the terms at the top. The solutions given by the quadratic equation are values of "x" that satisfy the equation.
Solve this quadratic equation using the quadratic formula 2x2 - 10x plus 7 equals 0?
2x2-10+7 = 0 Solving the quadratic equation using the quadratic formula will give you two solutions and they are: x = (5 - the square root of 11)/2 or x = (5 + the square root of 11)/2
What are the solutions for x2 minus 2x minus 12 equals 0?
Using the quadratic equation formula:- x = 1 +/- the sqrt of 13 = -2.60555 and 4.60555 (to 5 dp).
