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Q: What is the sum of all odd numbers to 99?

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The sum of all odd numbers 1 through 99 is 9,801.

answer:2500

100

99^2 == 9,801

99

100

9801 * The sum of the first two odd numbers (1+3) is 4, or 22 * The sum of the first three odd numbers (1+3+5) is 9, or 32 * The sum of the first four odd numbers (1+3+5+7) is 16, or 42 * ...and so on So the sum of the first 99 odd numbers, using the pattern above, would be 992 or 9801.

The sum of the even numbers is (26 + 28 + ... + 100); The sum of the odd numbers is (25 + 27 + ... + 99) Their difference is: (26 + 28 + ... + 100) - (25 + 27 + ... + 99) = (26 - 25) + (28 - 27) + ... + (100 - 99) = 1 + 1 + ... + 1 There are (100 - 26) ÷ 2 + 1 = 38 terms above which are all 1; their sum is 38 x 1 = 38. So the difference of the sum of all even numbers and all odd numbers 25-100 is 38.

The sum of 1+ 3 + 5 + ... + 99 = 50 x (1 + 99) ÷ 2 = 2500.

The sum of all the integers between 1 and 99 inclusive is 4950.

99 is an odd number. Even numbers are evenly divisible by two, while odd numbers are not.

let the number be n-1, n, n+1 then 3n=99 and so n=33 the numbers are 32, 33, 34

All of the odd numbers in that range can be factors.

The total of all of the numbers from 1 to 99 is 4950.

you can't

100

The odd numbers 1-99 will be a higher total than the even numbers 2-98

printf ("%d\n", (1+99)/2*50).

The composite odd numbers from 9 to 99.

99

The numbers are 31, 33 and 35.

4950

Infinity

Since we are talking for the sum of digits, then we are talking about 2-digit numbers between 1 and 100, which are 90 numbers (10 to 99). From these numbers only half of them satisfy the above condition, that is 45 numbers. So 50% of 2-digit numbers between 1 and 100 have an odd sum of their digits.

101