the answer is 20
As it is a hole there is no dirt in it. However, a cylinder of dirt with radius 1.5ft, depth 5ft and a volume of πr2h ~= 35.34 cu ft has been removed.
3.4 miles is 17952ft r2 = 4400/17952pi r= 0.28 ft
Suppose the diameter of the disk is D cm so that the radius is D/2 = R cm. Suppose the diameter of the hole is d cm so that its radius is d/2 = r cm. Then the area of one side of te disc is pi*(R^2 - r^2) Therefore the total area of the two sides is 2*pi*(R^2 - r^2) square cm. This ignores the surface area of the edge which, although small, is not 0.
No. Radius is half of the diameter.
If it had a radius, then it wouldn't be a singularity. The event-horizon surrounding a black hole has a radius, which depends on the black hole's mass. But the singularity itself has no radius.
The Schwartzchild radius.
It is called the Schwarzschild radius
The Schwarzschild radius is a theoretical radius a thing(here: Sun) would need to be compressed to to become a black hole.
The black hole property that determines the Schwarzschild radius of the black hole is that it has mass but no angular momentum nor electric charge.
Anything within the Schwarzschild radius can't escape from the black hole, even at the speed of light.Anything within the Schwarzschild radius can't escape from the black hole, even at the speed of light.Anything within the Schwarzschild radius can't escape from the black hole, even at the speed of light.Anything within the Schwarzschild radius can't escape from the black hole, even at the speed of light.
the answer is 20
The Schwarzchild radius of a 2 solar mass black hole would be about 5.9 km.
the hole has a 20 foot diameter and a 10 foot radius
The event horizon of a black hole is a spherical area round the center of the black hole; it has a radius proportional to the mass of the black hole - a radius of about 2.95 kilometers for every solar mass.
The escape velocity reaches the speed of light at the Schwarzshild radius.
you lick my butt hole..