'Range' is the difference between the lowest datum and the highest. When dealing with a set of data, it is often convenient to first arrange the datum from lowest to highest: 149, 247, 327, 470, 498, 562, 568 The range is 568 minus 149, or 419.
The whole number of 247 is between the whole numbers of 246 and 248
247 + 398 = 645398 - 247 = 151Therefore the two numbers which add together to make 645 and have a difference of 151 are 247 and 398.
645 - 151 = 494 494 / 2 = 247 247 + 151 = 398 Which means: 398 + 247 = 645 and 398 - 247 = 151
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398 and 247.
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247, 494 (=247*2), 741 (=247*3) etc.
1, 13, 19 and 247.
There are no two numbers between 10 and 20 with a product of 247.
The whole number of 247 is between the whole numbers of 246 and 248
It is: 676-247 = 429
1 13 19 247.
The two prime numbers 13*19=247
247 + 398 = 645398 - 247 = 151Therefore the two numbers which add together to make 645 and have a difference of 151 are 247 and 398.
All of the prime numbers (except 2) are odd. The sum of any two prime numbers (except 2) will be even. Unless 245 is a prime number (it isn't) your question does not have a solution.
645 - 151 = 494 494 / 2 = 247 247 + 151 = 398 Which means: 398 + 247 = 645 and 398 - 247 = 151
741 results from the following multiplications of two numbers: 1 * 741 (1 is not prime) 3 * 247 (247 is not prime) 13 * 57 (57 is not prime) 19 * 39 (39 is not prime) There are no two prime numbers that when multiplied equal 741. 3 * 13 * 19 equals 741, and all three of those numbers are prime.