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The smallest number is 1 and the largest number is 8. The range is the largest minus the smallest, so it is 8-1=7.
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What is the range of these list of ordered pairs (-3 -1) (0 -2) (4 3) (1 5)?
What is the range of function of y= 9x
Is it ever possible for the domain and range to have different numbers of entries what happens when this is the case?
Yes. Typical example: y = x2. To avoid comparing infinite sets, restrict the function to integers between -3 and +3. Domain = -3, -2 , ... , 2 , 3. So |Domain| = 7 Range = 0, 1, 4, 9 so |Range| = 4 You have a function that is many-to-one. One consequence is that, without redefining its domain, the function cannot have an inverse.
The lowest number of value?
In Excel you can use the SMALL() function The small function can retrieve the smallest values from data based on rank. For example: =SMALL(range,1) // smallest =SMALL(range,2) // 2nd smallest =SMALL(range,3) // 3rd smallest
What is the range of 3 3 4 2 1 3 3?
3,3,4,2,1,3,3 3-3=0 range=0
What is the range of the following set of numbers 2 1 3 4 4 4?
The range ot 2, 1, 3, 4, 4, and 4 is 3.
What is the range when the domain is -2 1 3?
That depends on the specific function.
Domain and range of binary function?
x y -3 2 -1 6 1 -2 3 5
What is the range of these list of ordered pairs (-3 -1) (0 -2) (4 3) (1 5)?
What is the range of function of y= 9x
What is the range of 5 2 1 3?
the range for 5 2 1 and 3 is 4.
What is the mean mode median and range of 1 2 3 3 1?
mean= 2, mode= 1 and 3, median= 3, and range= 2
If an inverse function undoes the work of the original function the original functions range becomes the inverse functions?
Maybe; the range of the original function is given, correct? If so, then calculate the range of the inverse function by using the original functions range in the original function. Those calculated extreme values are the range of the inverse function. Suppose: f(x) = x^3, with range of -3 to +3. f(-3) = -27 f(3) = 27. Let the inverse function of f(x) = g(y); therefore g(y) = y^(1/3). The range of f(y) is -27 to 27. If true, then f(x) = f(g(y)) = f(y^(1/3)) = (y^(1/3))^3 = y g(y) = g(f(x)) = g(x^3) = (x^3)^3 = x Try by substituting the ranges into the equations, if the proofs hold, then the answer is true for the function and the range that you are testing. Sometimes, however, it can be false. Look at a transcendental function.
Is it ever possible for the domain and range to have different numbers of entries what happens when this is the case?
Yes. Typical example: y = x2. To avoid comparing infinite sets, restrict the function to integers between -3 and +3. Domain = -3, -2 , ... , 2 , 3. So |Domain| = 7 Range = 0, 1, 4, 9 so |Range| = 4 You have a function that is many-to-one. One consequence is that, without redefining its domain, the function cannot have an inverse.
What is the range of a a function f when it is defined by f x 2 cos 3 x where x is a real number?
f(x) = 2 cos 3x The amplitude: A = |2| = 2 The maximum value of the function: 2 The minimum value of the function: -2 The range: [-2, 2]
The lowest number of value?
In Excel you can use the SMALL() function The small function can retrieve the smallest values from data based on rank. For example: =SMALL(range,1) // smallest =SMALL(range,2) // 2nd smallest =SMALL(range,3) // 3rd smallest
What is the range of the given function?
{(-2,0),(-4,-3),(2,-9),(0,5),(-5,7)}
What is the range of 3 3 4 2 1 3 3?
3,3,4,2,1,3,3 3-3=0 range=0
What is the range of the following set of numbers 2 1 3 4 4 4?
The range ot 2, 1, 3, 4, 4, and 4 is 3.
