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The rate of changing the interval of 25 is 19.5. This is a math problem.
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What is the rate of change in a linear relationship?
The rate of change equals the slope. In the basic formula y=mx+b, the rate of change is equal to m. In the equation y=5x+3, the rate of change equals 5.
How do you use the points in each coordinate grid to determine what scale interval was used on each axis?
I'm not sure I understand your question, but if the point (10,6) is plotted 2 squares to the right of the origin and 3 squares up, then the horizontal scale interval is 5 and the vertical scale interval is 2. Each horizontal space represents 5; each vertical space represents 2.
What is class interval size?
The class interval for each interval is the difference between its upper limit and its lower limit.
How do I write an interval notion and graph it...it is a set of real numbers that would be less than or equal to -4?
For an interval of numbers, two types of brackets are used, [] and (), the first signifies that interval includes the number before/after it and the latter indicate the interval includes everything upto that value.e.g.[0,2] indicates an interval of all real numbers from 0 to 2 including those numbers(-1,6) indicates an interval of all real numbers between -1 and 6 but not -1 and 6 themselves[5,12) indicates an interval of all real numbers from 5 upto but not including 12and (-9,-2] indicates an interval of all real numbers from -2 down to but not including -9.so, an interval of real numbers less than and equal to -4 would be (-­∞,-4], we use a ( for -∞ as, obviously, infinity can never be reached.To graph line intervals, we use a solid line along the interval and use filled circles, •, to signify that the point it is on is included in the interval, and empty circles, ○, to signify the point it is on is not included in the interval. So an interval of [5,12) would be drawn like this,•--------------------○5 6 7 8 9 10 11 12the drawing for (-­∞,-4] would simply be a straight solid line from the end of the negative side of the number line upto -4 with a • to show that -4 is included.
What is the most reasonable interval for the data 5 10 30 40 20?
A good way to assess what is a reasonable interval when graphing data is to see if there are any common factors in the data set. In this case 5, 10, 30, 40 and 20 are all clearly divisible by 5. Therefore, 5 would be a reasonable interval to use when graphing the data.
How do you find instantaneous acceleration from 5 m s to 25 m s is 4 seconds What is the rate?
Acceleration = rate of change of speed = (change of speed) / (time interval) = (25 - 5) / 4 = 20/4 = 5 m/s2
What if someone used green antifreeze in your DEX cool system?
The antifreeze change and flush interval is changed from what the owners manual says, Usually every 5 years.The interval is now 2 years.
Can you find the rate of change for the following problem Birds 2 5 8 11 Bird Cages 2 4 6 8?
The rate of change is 2 cages per 3 birds.
How do you change 2 7fifths to percent?
2 7/5 = 17/5 = 3.4 % rate = 3.4 x 100% = 340% Answer: 2 7/5 = 340%
Which Is greater 2-3 or 5-7?
The numeric interval of 5-7 is greater.
Is 3 to 5 is two hours?
The interval between 3 and 5 is indeed 2.
What mileage to change cambelt on Mitsubishi Space Star 1.3?
The cambelt change interval is every 5 years or 54'000 miles
What is the interval of 5?
5
How do you graph the interval of negative two is less than or equal to x which is less than five?
This can be written as -2 < x < 5. A graph of this interval is a straight line segment with a left side marked "-2", a right side marked "5", and some convention or note indicating that the interval is closed on the left side but open on the right. One possibility is: [________________). -2 ............................. 5
What is the rate of change in a linear relationship?
The rate of change equals the slope. In the basic formula y=mx+b, the rate of change is equal to m. In the equation y=5x+3, the rate of change equals 5.
What is the most reasonable interval for the data 2 4 1 7 5?
1
What is a car's acceleration if it increases its speed from 5 meters per second to 20 meters per second in 3 seconds?
In general, the acceleration during that time interval could vary considerably. However, we can calculate the average acceleration during the interval. The change in speed is 20 meters per second - 5 meters per second = 15 meters per second, and this change in speed occurs over a 3 second interval. Thus the average change in speed over this interval is 15 meters per second/ 3 seconds = 5 meters per second per second = 5 meters/second2
