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Q: How many prime numbers are in the prime factorization of 289?

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289 does.

289 = 17 x 17

17 x 17 = 289

289 = 17 x 17

289 17,17

The prime factorization of 867 is: 3 x 289 3 x 17 x 17 The two prime factors of 289 are 3 and 17.

17 x 17

The prime number (factor) of 289 is: 17

289 = 17^2 17 x 17

17 x 17 = 289

The prime factors of 289 are 17 and 17 (i.e. 289 = 17*17).

its prime

121, 169, 289

17 and 17

There is no solution. For two numbers to add to an odd total, one of them must be even. If that number is also a prime it must be 2. But if one of the numbers is 2 and the two sum to 289, the other must be 287. But 287 is not a prime and the question required two primes to be added.

It is impossible to list all squared prime numbers as there is an infinite number of squared prime numbers starting with 4, 9, 25, 49, 121, 169, 289, 361, 529, 841,...

No - The prime factors of 289 are 17 and 17.

The Prime Factor of 289 is 17

289 is a composite number. This is because composite numbers are any number that has more than two factors(one and itself). Therefore, since 17 is a factor of 289 that makes it a composite number.

Prime squares like 121, 169 and 289.

1, 17, 289 17 is prime.

17*17 = 289

289 is an odd number so it must be the sum of an odd and an even number. The only even prime number is 2 so the other number must be 287, which is not prime as it is divisible by 7, so your question has no answer in this universe.

289 = 17 x 17

289 is composite. 289 = 17 * 17 = 172