8b + 11 - 3b = 2b + 2 5b + 11 = 2b + 2 5b - 2b = 2 - 11 3b = -9 b = -3
a2 - 2ab - 15b2 = (a - 5b)*(a + 3b)
b over the square root of 5 The square root of 5b squared is 5b, and the simplified form of the square root of 125 is 5 root 5. The 5s then cancel out leaving b over the square root of 5.
No. 7b - 2b = 5b
-b+5b-2b=2b
3a + (3b - 2a) + 5b =3a + 3b - 2a + 5b =(3a - 2a) + (3b + 5b) =a + 8b
add like terms: 3a -2a -5b + 6b +3b - 7b = a -3b
5b plus 5-3b-7 is 2b-2.
They are like terms and can be added simply as 5b
We can combine the like terms. So the b2 can be combined with the 2b2 to give 3b2. Likewise the 3b plus the -5b gives -2b.Therefore, b2 + 3b - 5b + 2b2 = 3b2 - 2b.
here is how you go about solving it first write down the question 3b+4+5b-1 then change arrangement so that it looks like this 3b+5b+4-1 then solve 8b+3
5b + 11 - 2b = 3b + 11
8b + 11 - 3b = 2b + 2 5b + 11 = 2b + 2 5b - 2b = 2 - 11 3b = -9 b = -3
3a - 2b
8b -2a
5b - 3 - 2b = 6b - 3 3b - 3 = 6b - 3 3b - 6b = 3 - 3 b = 0
5+3b? :3