Q: What is the rule of divisible by 6?

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Rule: If it is divisible by 2 and by 3Numbers are divisible by 6 if they are divisible by 3 and 2. Therefore, for example, since 18 is divisible by 3 and 2, it is also divisible by 6.The divisibility rule for 6 is, it can go into the number if 2 and 3 can also.

If a number is even and divisible by 3, it's divisible by 6.

The number must be divisible by both 2 and 3 for it to be divisible by 6.

if the number is divisible by 2 and 3 then it is divisible by 6 =D

So pretty much it is the same rule as 4 and 6 because both # go into 24. 4 rule: look at the last to places to see if the # is divisible by 4. 6 rule: if the #is both divisible by 2 and 3 then it s divisible by 6.

The Rule for 4 is if the last 2 numbers are divisible by 4 (The tens and ones place) For example. 10759283740 is divisible, while 10759283738 is not, because 4 does not go into 38. The rule for 6 is if the number is even and also divisible by 3. If this is true, then the number is divisible by 6.

Numbers are divisible by 6 if they are even and also divisible by 3. Therefore, for example, since 18 is divisible by 3 and 2, it is also divisible by 6.

If a number is divisible by 2 (an even number) and 3 (the sum of the digits is divisible by 3) then the number is divisible by 6.

It has to be divisible by 2 and 3 .

If a number is divisible by both 2 and 3, that number will also be divisible by 6. Hope this helps!

Because 9 is divisible by 3, this is like the rule where if a number is divisible by 2 and 3 it is also divisible by 6.

Numbers are divisible by 6 if they are even and also divisible by 3. examples are 6,12,18,24,30,36,60,54,...... examples as algebric expressions 18xy+12z+6y-a,where a is divisible by 6 i.e 6,12,18...

A number has to be even and also divisible by 3.

It is easy to see if 221 is divisible by 6. The number 6 is even and 221 is not. An even number cannot evenly divide an odd number . You get: 36.8333333... recurring A handy rule is: Any number is divisible by 6 if it is divisible by both 2 and 3.

If the last digit (6) is divisible by 2 - that is, it is 0, 2, 4, 6 or 8 then the number is divisible by 2. Note that this rule cannot be used to check for divisibility by other numbers.

342 is divisible by 6 and not 5.Numbers divisible by 5 end in zeros or fivesNumbers divisible by 6 have a slightly more complicated rule. If, when the individual digits are added together and they make a multiple of 3, see if the number is even. If so, and the digits add up to a multiple of 3, then the number is a divisible by 6.

the divisibility rule for 2 is: The number is even;the last digit ends with a 2,4,6,8,10, etc.The divisibility rule fir 3 is: The sum of the number is divisible by 3The divisibility rule for 4 is: The last two digits are divisible by 4The divisibility rule for 5 is: The number ends with a 5 or 0The divisibility rule for 6 is: The sum CAN be divisible by 2 and or 3The divisibility rule for 9 is: The sum of the number is divisible by 9The divisibility rule for 10 is : The number ends with a 0

The divisibility rule of 3 is that you add the digits together and then if the number you come up with is divisible by 3, then the number itself is divisible by 3. In this instance, 5 + 8 + 5 = 18/3 = 6, therefore, 585 is divisible by 3.

no. Here is a rule to learn- If a number is divisible by 5, it must end in 0 or 5. If it does not, it is not divisible by 5. Numbers that end in 1,2,3,4,6,7,8,9 are NOT divisible by 5. (Conversely,) if the number does end in 0 or 5 , it is divisible by 6.

6 is not divisible by 162. 162 is divisible by 6.

2+6+4+1=1313 is not divisible by 3 therefore 2641 ia not divisible by three.This rule works for 3, 9, 27 and 81

If a numbers digits add up to a number that is divisible by nine, the number is divisible by nine. Example~ 486 4+8+6=18 Since 18 is divisible by 9, 486 is divisible by 9. 561 5+6+1=12. 561 isn't divisible by 9.

To be divisible by 6, the number must be divisible by both 2 and 3:To be divisible by 2 the last digit must be even, ie one of {0, 2, 4, 6, 8};To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3.As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3.If the number is not divisible by 2 or 3 (or both) then the number is not divisible by 6.examples:126Last digit is even so it is divisible by 2 1 + 2 + 6 = 9 which is divisible by 3, so it is divisible by 3â†’ 126 is divisible by both 2 and 3, so it is divisible by 6124Last digit is even so it is divisible by 2 1 + 2 + 4 = 7 which is not divisible by 3, so it is not divisible by 3â†’ 126 is divisible by 2 but not divisible by 3, so it is not divisible by 6123Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 3 = 6 which is divisible by 3, so it is divisible by 3â†’ 123 is divisible by 3 but not divisible by 2, so it is not divisible by 6121Last digit is not even so it is not divisible by 2 We can stop at this point as regardless of whether it is divisible by 3 or not, it will not be divisible by 6. However, for completeness:1 + 2 + 1 = 4 which is not divisible by 3, so it is not divisible by 3â†’ 121 is not divisible by either 2 or 3, so it is not divisible by 6

The divisible rule for 2 is if the last digit of the number is 0,2,4,6, or 8. The divisible rule for 3 is if the last 2 digits of the number is divisible by 3,03,06,09,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96, or 99.

If a number is divisible by 2 and 3, it is divisible by 6.

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