sec(27) = 1.1223, approx.
1.122
1.269
An angle of 27 degrees is an acute angle
The complement of a 27-degree angle is the angle that, when added to the original angle, equals 90 degrees. Therefore, the complement of a 27-degree angle would be 63 degrees.
an acute angle because it is less than 90 degrees!!
sec 45o = cosec 45o = √2 ≈ 1.414
Sec(27) = 1/cos(27) = 1/0.891 = 1.1223 approx
1.269
An angle of 27 degrees is an acute angle
The complement of a 27-degree angle is the angle that, when added to the original angle, equals 90 degrees. Therefore, the complement of a 27-degree angle would be 63 degrees.
an acute angle because it is less than 90 degrees!!
180-27 = 153 degrees
Find the cosine of 38 degrees and then find its reciprocal.
sec 45o = cosec 45o = √2 ≈ 1.414
A good approximation: Velocity = (331 + 0.6*Tc) m/sec where Tc is in Centigrade, not Kelvin V (at 27C) = (331 +0.6*27)m/sec = 347.2 m/sec
A right triangle that is also isosceles cannot have an angle of 57 deg 24 sec unless it is in spherical - as opposed to plane, or flat - space.
7*2=14(which is less than 90 degree so that's it Acute angle)
A pair of supplementary angles add up to 180 degrees. Therefore, the supplement to a 105 degree angle is equal to 180 - 105 = 75 degrees.