0
10-2x for x = 0, 1, 2, 3, ...
Since the domain of an arithmetic sequence is the set of natural numbers, then the formula for the nth term of the given sequence with the first term 10 and the common difference -2 is
an = a1 + (n -1)(-2) = 10 - 2n + 2 = 12 - 2n.
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The numbers one to ten, in alphabetical order of their names in English.
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10
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The answer is 10!/[6!*(10-6)!] where n! represents 1*2*3*...*n Number of combinations = 10*9*8*7*6*5*4*3*2*1/(6*5*4*3*2*1*4*3*2*1) = 10*9*8*7/(4*3*2*1) = 210
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10, 8, 6, 4, 2, 0, -2, -4
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10
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10
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-34
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Un = 2n + 2 is one possible answer.
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