4.884 has four significant figures and 2.25 has three significant figures. 4.884 x 2.25 = 10.989 = 11.0 rounded to three significant figures. When multiplying or dividing, the result must have the same number of significant figures as the number in the problem with the fewest significant figures.
The number 1.84 x 103 has three significant figures, 1.84. The 103 part of the number does not count when determining significant figures.
5.0 x 10^2
That measurement has 4 significant figures. It could also be stated as 1.580 x 10^-3.
The LEFT zeros are place holders, which are not contibuting to significance.0.0360 = 3.60 X 10-2So, actually, there are 3 significant digits. The '3' and '6' and the '0'; this one -AFTER the 6- is not a place holderbut an indicator of the precision of the number - a significant digit.0.036 has 2 significants, and 0.0360 has 3 significant numbers.
1.70 x 10^5
It has 5 significant figures - one trailing zero is significant.
Significant figures are very important when it comes to calculations. If the mass of an electron is 9.10939 x 10-31 then its significant figures are: 9 x 10^-31( correct 1 significant figure), 9.1 x 10^-31 kg ( correct to 2 significant figures), 9.11 x 10^-31 (correct to 3 significant figures), and 9.109 x 10^-31 (correct to 4 significant figures).
When multiplying, the number of significant numbers in the answer should be the same as the fewest significant figures in the problem. Both 13.5 and 3.00 have three significant figures, so the answer will have three significant figures. 13.5 x 3.00 = 40.5 exactly (no need to round).
29.05 to 3 significant figures
6.5211 x 104 = 678.1944 678.1944 has 7 significant figures
There are 2 significant figures in 7.8x109^?
There are two significant figures which are the 5 and the 4. 0.054 = 5.4 x 10^-2
The number 1.84 x 103 has three significant figures, 1.84. The 103 part of the number does not count when determining significant figures.
5 significant figures Each figure that contributes to the accuracy of a value is considered significant. So 2.9979 has 5 significant figures. The 10^8 does not contribute to the accuracy as it simply indicates the number of trailing zeroes (i.e. 299,790,000) that are simply a result of rounding from the actual value (299,792,458)
(4.73*1000*0.568)+1.61 = 2688.25 meaning that it has 6 significant figures
In both cases, there are 2 significant figures.
5 since 1.0400 has 5 significant figures. when dividing or multiplying go with the number with the smaller significant figures.