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When multiplying, the number of significant numbers in the answer should be the same as the fewest significant figures in the problem. Both 13.5 and 3.00 have three significant figures, so the answer will have three significant figures. 13.5 x 3.00 = 40.5 exactly (no need to round).
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∙ 11y ago
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∙ 7y agoThe least number of significant figures in any number of the problem determines the number of significant figures in the answer.
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How many significant figures in this number 7.8 x 10?
There are 2 significant figures in 7.8x109^?
What are the significant figures for 0.054?
There are two significant figures which are the 5 and the 4. 0.054 = 5.4 x 10^-2
How many significant figures in this number 7.8 x 10 and sup1 and sup2?
In both cases, there are 2 significant figures.
How many significant figures would be in the answer of 2.2458 m x 0.55 m?
Two. When multiplying or dividing the answer is rounded to the fewest significant figures in the given measurements. 0.55 has only two significant figures, so the answer can have only two significant figures.
75.6 x 12.33 in significant figures?
Count the significant figures in each number. Calculate the minimum of these numbers. Do the multiplication Round the product to the LEAST number of significant figures, determined above.
How many significant figures are in 3001?
300 only has one significant digit.
What is the significant figures 4.884 x 2.25?
4.884 has four significant figures and 2.25 has three significant figures. 4.884 x 2.25 = 10.989 = 11.0 rounded to three significant figures. When multiplying or dividing, the result must have the same number of significant figures as the number in the problem with the fewest significant figures.
If the mass of an electron is 9.10939 x 10-31 then show 1 2 3 and 4 of its significant figures?
Significant figures are very important when it comes to calculations. If the mass of an electron is 9.10939 x 10-31 then its significant figures are: 9 x 10^-31( correct 1 significant figure), 9.1 x 10^-31 kg ( correct to 2 significant figures), 9.11 x 10^-31 (correct to 3 significant figures), and 9.109 x 10^-31 (correct to 4 significant figures).
How many significant figures are in 3.4 x 1705?
It has 5 significant figures - one trailing zero is significant.
What is 45 of 300?
To find 45 percent of a number, multiply the number by 0.45. In this instance, 0.45 x 300 = 135. Therefore, 45 percent of 300 is equal to 135.
How many significant figures in 3.895?
29.05 to 3 significant figures
How many significant figures are in 6.5211 X 104after appropriate rounding?
6.5211 x 104 = 678.1944 678.1944 has 7 significant figures
How many significant figures in this number 7.8 x 10?
There are 2 significant figures in 7.8x109^?
What are the significant figures for 0.054?
There are two significant figures which are the 5 and the 4. 0.054 = 5.4 x 10^-2
How many significant figures are in 1.0 X 102?
The number 1.84 x 103 has three significant figures, 1.84. The 103 part of the number does not count when determining significant figures.
How many significant figure for 2.9979 x 108?
5 significant figures Each figure that contributes to the accuracy of a value is considered significant. So 2.9979 has 5 significant figures. The 10^8 does not contribute to the accuracy as it simply indicates the number of trailing zeroes (i.e. 299,790,000) that are simply a result of rounding from the actual value (299,792,458)
What is the significant figures for ( 4.73 x 1000 x 0.568 ) plus 1.61?
(4.73*1000*0.568)+1.61 = 2688.25 meaning that it has 6 significant figures
