x - 1 is in its simplest form.
x-1 is the simplest form.
point slope form is y-y1=m(x-x1). x1 and y1 are both points and m is the slope.
-x1
If (x1, y1) and (x2, y2) are two points on the line, then the formula for the slope is (y2-y1)/(x2-x1) provided x2 ≠x1. If x2 = x1 then the line is vertical and the slope is not defined.
(y-y1)=m(x-x1) OR we can write it y=m(x-x1)+y1
Point-slope form is written as: y-y1=m(x-x1), where (x1, y1) is a point on the line and m is the slope (hence the name, point-slope form).
Simplest form
two points form a line. (x1,y1)(x2,y2)
X1 = -81
Although there are formal methods, the simplest is to see if the cubic can be factorised. If so, you'll have a linear factor and a quadratic, both of which are easy to solve. Alternatively, you could try solving it graphically. Another possibility is to solve it numerically. The derivative of a cubic, of the form f(x) = ax3 + bx2 + cx + d is f'(x) = 3ax2 + 2bx + c. Make an initial estimate x1. An improved estimate is x2 = x1 - f(x1)/f'(x1). Use x2 to make next estimate, and so on.
3/7 is in its simplest form.
Y-y1=m(x-x1)
y-y1=m(x-x1) this is the answer