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Q: How can you check if a number is divisible by 9 when usimg?

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To check for divisibility by 9 sum the digits of the number and if this sum is divisible by 9 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 9 so 32643 is divisible by 9. As 9 = 3 × 3, any number divisible by 9 is also divisible by 3, thus as 32643 is divisible by 9 it is also divisible by 3. However, for completeness: to check for divisibility by 3 sum the digits of the number and if this sum is divisible by 3 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 3 so 32643 is divisible by 3.

No. To check divisibility by nine, sum the digits. If they add up to 9 (or a multiple of 9) then the number is divisible by 9. This trick works for 9 divisibility and 3 divisibility. In this problem: 3 + 0 + 9 + 1 = 13, which is not divisible by 9. Suppose the number was 3591: 3+5+9+1=18, which is divisible by 9 (you can check 1+8=9). You can keep summing the digits of the new numbers till you get to a number which is either 9 or some other number. (If it's 3 or 6, then the number is divisible by 3)

No. To check if a number is divisible by 9 add the digits together and if the sum is divisible by 9 then so is the original number. The check can be used on the sum so keep summing until a single digit remains. If this digit is 9, then the number is divisible by 9, otherwise it gives the remainder when the number is divided by 9. (This single digit is known as the digital root of the number.) 104 → 1 + 0 + 4 = 5 5 is not 9, so 104 is not divisible by 9; it has a remainder of 5 when divided by 9

702 ÷ 9 = 78 Therefore, the answer is , Yes. ---------------------------------------------------------- To check if a number is divisible by 9 add the digits together and if the sum is divisible by 9 then so is the original number. The check can be used on the sum so keep summing until a single digit remains. If this digit is 9, then the number is divisible by 9, otherwise it gives the remainder when the number is divided by 9. (This single digit is known as the digital root of the number.) 702 → 7 + 0 + 2 = 9 9 is 9, so 702 is divisible by 9.

If a number is not divisible by 3 then it is not divisible by 9.

No, it is not divisible by 9. To check if a number is divisible by 9 add all the digits together and if this sum is divisible by 9, then so is the original number. As the check can be applied to the sum, keep adding the digits together until a single digit remains. If this digit is 9, then the original number is divisible by 9 (otherwise it gives the remainder when the original number is divided by 9). for 345: 3 + 4 +5 = 12 for 12: 1 + 2 = 3 which is not 9, so 345 is not divisible by 9. (The remainder when 345 is divided by 9 is 3.)

Yes, every number that's divisible by 9 is divisible by 3

add all the digits of the number and check if it is divisible by 3. eg-3321=3+3+2+1=9=divisible by three.the same works for 9.

Yes, any number divisible by 9 is also divisible by 3.

9101997 has factors other than 1 and itself, so it is not a prime number. For example, it is divisible by 3. (You can check this by adding the digits of the number: 9 + 1 + 0 + 1 + 9 + 9 + 7 = 36, which is divisible by 3. If the sum of the digits is divisible by 3, the number is also divisible by 3.) Therefore, 9101997 is a composite number.

No. To check for divisibility by 9 add the digits together and if this sum is divisible by 9 then so is the original number. This can be repeated until a single digit remains which must be 9 for the original number to be divisible by 9. For 98: 9 + 8 = 17 → 1 + 7 = 8 which is not 9, so 98 is not divisible by 9.

No - any number divisible by 9 will have the sum of its digits divisible by 9.

Every number is divisible by 9 but the answer wont necessarily be a whole number.

9 is divisible by 1, 3 and 9.

If all the digits add up to 9 then it is divisable by 9

A number is divisible by 9 of its digits add up to a multiple of 9.

None, because 9 is divisible by 3.

Nope. With any number, to check if it's divisible by 9, add all the digits together. If the result can be divided by 9, then the original can be too. In this case, 5+7+6+8 totals 26 - not divisible by 9.

yes, you know that because if you add the digits together and that number is divisible by 9, then that large number is divisible by 9. 3+4+2 is 9, which is divisible by 9. conclusion 342 is divisible by 9.

999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer. Some shortcuts for divisibility: 0 is divisible by any number. If the last digit of a number is divisible by 2, the number itself is divisible by 2. If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3. If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4. If the last digit of a number is divisible by 5, the number itself is divisible by 5. If a number is divisible by both 2 and 3, it is divisible by 6. If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8. If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9. 990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9. 18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.

77922 is divisible by 6. 77922 / 6 = 12987 To check if a number is divisible by 6, the number has to be even and divisible by three. An easy way to check if a number is divisible by three is to see if the sum of the digits is divisible by three. 77922 7+7+9+2+2 =27 27 2+7 =9 9 is divisible by three, so 77922 is divisible by three also.

No. To check for divisibility by 9 add the digits of the number and if the sum is divisible by 9 then the original number is also divisible by 9, otherwise it is not. For 24815: 2 + 4 + 8 + 1 + 5 = 20 which is not divisible by 9, so 24815 is not divisible by 9. Note that the test can be applied to the sum: repeatedly summing the digits of the sum of the digits until a single digit remains means the original number is divisible by 9 only if this single digit is 9, otherwise it is not (instead it gives you the remainder when the original number is divided by 9). This single digit is known as the digital root of the number.

If the digits of a number add up to a multiple of 9, the whole number is divisible by 9.

There is only one number in 3206 and that is 3206. And that, is not divisible by 9.

A number is divisible by 9 if a whole number of 9s can go into it and leave no remainder.