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Q: What remainders are possible when you divide a number by 6 by 4 by 9?

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4

In division by 5, you can have remainders of 0, 1, 2, 3, and 4. If you count zero, then you can have five possible remainders. If you are not counting zero, then 4 possible remainders.

assume dividing into whole number if you divide by 4 then remainder will be 0,1,2, or 3 by 6 then remainder will be 0,1,2,3,4 or 5 by 9 then remainder will be 0,1,2,3,4,5,6,7 or 8

the max remainder you can have when dividing by a number is that number minus 1 So 4 can only have 1, 2 and 3 as remainders. 9 can only have 1-8 and so on.

The possible number of remainders is always one less than the divisor.

With the divisor (the number you are dividing by) as 9, there are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, and 8.

2

There are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, 8.

20 / 4 = 5 (no remainder) 21 / 4 = 5 remainder 1 22 / 4 = 5 remainder 2 23 / 4 = 5 remainder 3 24 / 4 = 6 (no remainder) Therefore the numbers that can remain after you've divided a number by four are 0, 1, 2, and 3.

0.75

The possible remainders are {0, 1, 2, 3, 4, 5, 6, 7} making eight of them.

Only 3 non-zero remainders.1, 2, and 3 are the only possible non-zero remainders since any number greater than or equal to the divisor could also be divided, to result in a new quotient. A remainder of zero, means that the dividend is divisible by the divisor (the divisor is a factor of the number)

No.

23.25

Because 4 will divide evenly into both numbers leaving no remainders

If you take any four consecutive numbers and divide them by 3, the remainders are as follows: 9/3 = 3 10/3 = 3 remainder 1 11/3 = 3 remainder 2 12/3 = 4 Therefore, the highest remainder you can have by dividing a whole number is 2.

There are 8 possible remainders; they are: 0 (or no remainder), 1, 2, 3, 4, 5, 6 and 7.

Remainders are normally thought of as what's left when you have accounted for as many a possible whole number multiples of the divisor (here 4). But if you have 5 left over then there's another 4 to go. There's no law against it but it would be a bit peculiar to say that 5 divided by 4 is zero with remainder 5. Arguably, you haven't completed the division properly. Try sharing 5 cakes amongst 4 people like that and see what trouble you will get into.

you multiply across. ex.(3/4=2/x you do 2 times 5 because you cant multiply 3 times x) then you divide by the number that is left over with the product but their shouldn't be any remainders but their can be a decimal. when you get the answer you put the number like x=?

4

Hexadecimal number let's say 5B1 B is 11 why? 10 = A 11 = B 12 = C .. .. .. .. ... up to 15 which is F in Hexa. Take 5111 and divide this by 4 5111/4 write down all remainders Write the answer to the top from last remainder which is the answer.

2401 is one such number.

-18

a wide array of numbers... here is one 52/8 = 6 and remainder 4

Divide the number of possible even numbers by all the possible numbers. So there are three possible even numbers; 2, 4 & 6. And there are six possible numbers; 1, 2, 3, 4, 5, & 6. So the probability of throwing an even number is 3/6 = .5 .