2x + 3y = 5 So 3y = -2x + 5 or y = -2/3x + 5 Now that the equation is in standard form, you just read the slope off as the coefficient of x, ie slope = -2/3
Since the equation is written in the form y = mx + c, the slope is simply m. In this case, m = 2.
y - 2x is not an equation. If that is supposed to be y = 2x then the slope is 2. Or, written as a slope, would be 2/1
[ y = 2x + 5 ] has a slope of 2. [ y = 2 ] is a horizontal line ... its slope is zero. Their slopes are different, so they're not parallel.
rewrite the equation in terms of y y = 1-2x the slope is -2
y=2x+7. The 2 is your slope and the 7 is your y intercept.
It is 3 and the slope is -2
The slope is the coefficient of x in the standard form and so it is 2.
The slope of the line of 2x plus 2y equals 7 is (7/2x - 1).
Is the equation of a straight line with slope 2 and an intercept of (0,20).
the slope is 2, the number in front of the 'x' term
In order to find slope, the equation must be in the form y = mx + b, with m being the slope. The original equation is y + 2x = -1 Solving for y makes the equation: y = -2x - 1 Therefore, the slope is -2
y = -2x+4 It can be any equation providing the slope is the same but the y intercept is different
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
2x-7y=14 2x-14=7y from this equation the slope is 2/7