Points: (6, -10) and (-15, 15)
Slope: (-10-15)/(6--15) = -25/21
-5
6x - 5y = 15 6x - 6x - 5y = 15 - 6x -5y = -6x + 15 (-5y)/-5 = (-6x)/-5 + 15/-5 y = 6/5x - 3 where 6/5 is the slope and y-intercept is -3.
Equation: y-6 = 2/5(x-10)Solution: 5y = 2x+10
Points: (0, 6) and (6,0) and the slope of the line works out as -1
If you mean points of (-10, -6) and (-1, 8) then the slope of the line is 14/9 which is in a positive direction
Points: (3, 3) and (-6, -15) Slope works out as: 2
Points: (0, 5) and (10, -15) Slope: -2
EQ2
Points: (10, 8) and (15, 8) Slope: 0 It will be a straight horizontal line
slope is =( 9-15 )/ (5-3) = -6/2 = -3
6x = 10-y y = -6x+10 The slope is -6 and the y intercept is 10
15
10
-5
if you mean points of (-6, 2) and (4, 1) then the slope works out as -1/10
7 or 10 if you calculate using the upward force slope then it is 10 otherwise it is 7! :0Another Possibility:-Using: y2- y1over x2-x1 = -2-2/2-6 = a slope of 1
Slope = -6/5 = -1.2 y-intercept = -3