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Pamela Ferry

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3y ago
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12y ago

It is the positive reciprocal of -11/13 which is 13/11

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Q: What is the slope of a line perpendicular to a line with a slope of -11 divided by 13?
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What is perpendicular to y equals 7x-4?

11


What is the slope of a line perpendicular to a line with a slope of zero?

To find the slope of a perpendicular line, take the negative reciprocal of the slope of the given line. (Flip the top and bottom of the fraction and change the sign.) The slope of a line that is perpendicular to a line with a slope of -2/3 is 3/2, (or 11/2 or 1.5).


What is the perpendicular bisector equation of the line joined by the points -2 5 and -8 -3 on the Cartesian plane?

Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-1 = -3/4(x--5) => 4y = -3x-11 Perpendicular bisector equation in its general form: 3x+4y+11 = 0


What is the perpendicular equation in its general form that meets the line whose coordinates are 2 5 and 11 17 at its midpoint on the Cartesian plane showing all work?

Points: (2, 5) and (11, 17) Midpoint: (6.5, 11) Slope: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-11 = -3/4(x-6.5) => 4y = -3x+63.5 In its general form: 3x+4y-63.5 = 0


What is the perpendicular bisector equation that meets the line segment of -2 2 and 6 4 at its midpoint showing work?

Points: (-2, 2) and (6, 4) Midpoint: (2, 3) Slope: 1/4 Perpendicular slope: -4 Perpendicular bisector equation: y-3 = -4(x-2) => y = -4x+11


What is the perpendicular bisector equation of the line whose end points are at 3 5 and 7 11 on the Cartesian plane?

Points: (3, 5) and (7, 11) Midpoint: (5, 8) Slope: 3/2 Perpendicular slope: -2/3 Perpendicular equation: y-8=-2/3(x-5) => 3y-24=-2x+10 => 3y=-2x+34 Therefore the perpendicular bisector equation is: 3y = -2x+34


What is the equation and its perpendicular bisector equation of the line whose end points are at -2 3 and 1 -1 on the Cartesian plane?

Points: (-2, 3) and (1, -1) Midpoint: (-0.5, 1) Slope: -4/3 Perpendicular slope: 4/3 Equation: 3y = -4x+1 Perpendicular bisector equation: 4y = 3x+5.5


How do you find the equation of the perpendicular line bisecting the line segment of -2 5 and -8 -3?

if u don't now then i don't nowImproved answer as follows:-First find the mid-point of (-2, 5) and (-8, -3) which is (-5, 1)Then find the slope or gradient of (-2, 5) and (-8, -5) which is 4/3The perpendicular slope is the negative reciprocal of 4/3 which is -3/4So the perpendicular bisector passes through (-5, 1) and has a slope of -3/4Use y -y1 = m(x -x1)y -1 = -3/4(x- -5)y = -3/4x-11/4 which can expressed in the form of 3x+4y+11 = 0So the equation of the perpendicular bisector is: 3x+4y+11 = 0


What is the perpendicular bisector equation that meets the line whose end points are at -2 plus 5 and -8 -3?

Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Perpendicular bisector equation: y-1 = -3/4(x--5) => 4y-4 = -3x-15 => 4y = -3x-11


What is the slope of the line givin by the equation y11x?

If you mean y = 11x then the slope is 11


What is the perpendicular bisector equation joining the line segment of -2 plus 5 and -8 -3 giving brief details?

Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Use: y-1 = -3/4(x--5) Bisector equation: y = -3/4x-11/4 or as 3x+4y+11 = 0


What is the slope if the line y equals 5X -6?

11